An alkyne with the molecular formula C5H8 was reduced with H2 and Lindlar's catalyst. Hydroboration-oxidation of the resulting a
1 answer:
Since the addition of the H2O in the last step of hydroboration is anti-Markovnikov, the starting material is 1-pentyne.
The addition of H2 to C5H8 yields an alkene when a Lindlar catalyst is used. Recall that the Lindlar catalysts poisons the process so that the addition do not go on to produce an alkane.
When hydroboration is carried out on the alkene, we are told that a primary alcohol was obtained. We must note that in the last step of hydroboration, water is added in an anti- Markovnikov manner to yield the primary alcohol. Hence, the starting material must be 1-pentyne as shown in the image attached.
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Explanation:
The given data is as follows.
= ?,
= 0.85 M
= 185 mL,
= 35.7 mL
where, is concentration of acid
is the volume of acid
is the concentration of base
is the volume of base
According to the neutralization formula.
=
Now, substituting the given values into the above formula as follows.
=
=
= 0.164 M
Thus, we can conclude that concentration of acid is 0.164 M.