To solve this question we must find the moles of iron(II) chloride that react. Using the chemical equation we can find the moles of iron(II) carbonate and its mass -Molar mass FeCO3: 115.854g/mol-

Moles FeCl2:

1.24L * (2.00mol / L) = 2.48 moles FeCl2

As 1 mol FeCl2 produce 1 mol FeCO3, the moles of FeCO3 = 2.48 moles

Mass FeCO3:

2.48mol * (115.854g / mol) =

<h3>The reaction can produce 287 grams of iron(II) carbonate</h3>

5 0

3 years ago

An animal cell placed in a hypertonic solution will shrink in a process called crenation. An animal cell placed in a hypotonic s

tresset_1 [31]

Answer:

Solution A: 3.21% (m/v) NaCl ⇒ CRENATION

Solution B: 1.65% (m/v) glucose ⇒ HEMOLYSIS

Solution C: distilled H₂O ⇒ HEMOLYSIS

Solution D: 6.97% (m/v) glucose ⇒ CRENATION

Solution E: 5.0% (m/v) glucose and 0.9%(m/v) NaCl ⇒ CRENATION

Explanation:

Isotonic solution = 0.9% (m/v) NaCl or 5.0% (m/v) glucose

Crenation will occur if the solution has a concentration higher than 0.9% (m/v) NaCl or 5.0% (m/v) glucose (hypertonic solution). This will occur in the following solutions:

Solution A: 3.21% (m/v) NaCl > 0.9% (m/v) NaCl

Solution D: 6.97% (m/v) glucose > 5.0% (m/v) glucose

Solution E: 5.0% (m/v) glucose and 0.9%(m/v) NaCl (the addition of the 2 components exceeds the osmotic pressure permitted).

Hemolysis will occur if the solution has a concentration lower than 0.9% (m/v) NaCl or 5.0% (m/v) glucose (hypotonic solution). This is the case of:

Solution B: 1.65% (m/v) glucose < 5.0% (m/v) glucose

Solution C: distilled H₂O = 0% glucose/0% NaCl < 0.9% (m/v) NaCl or 5.0% (m/v) glucose

3 0

3 years ago