Which of the following actions does not require power

A tank at is filled with of dinitrogen difluoride gas and of chlorine pentafluoride gas. You can assume both gases behave as ide

jenyasd209 [6]

The question is incomplete, the complete question is;

A 8.00 L tank at 2.64 °C is filled with 9.82 g of chlorine pentafluoride gas and 10.1 g of dinitrogen difluoride gas. You can assume both gases behave as ideal gases under these conditions. Calculate the mole fraction and partial pressure of each gas, and the total pressure in the tank. Be sure your answers have the correct number of significant digits.

Answer:

See explanation for details

Explanation:

Number of moles of N2F2 = mass/ molar mass

Molar mass of N2F2 = 66 g/mol

Number of moles = 10.1 g/66 = 0.15 moles

Number of moles of ClF5 = 9.82 g/130 g/mol= 0.08 moles

Molar mass of ClF5= 130g/mol

Total number of moles = 0.15 moles + 0.08 moles = 0.23 moles

Given that;

T= 2.64 °C + 273 = 275.64 K

n= 0.23 moles

R= 0.082 Latmmol-1K-1

V= 8.00 L

P= ??

From;

PV =nRT

P= nRT/V

P= 0.23 ×0.082 × 275.64/8.00

P= 0.65 atm

Mole fraction of N2F2= 0.15/0.23 = 0.65

Partial pressure = mole fraction × total pressure = 0.65 × 0.65 = 0.42 atm

Mole fraction of ClF5 = 0.08/0.23 = 0.35

Partial pressure of ClF5 = mole fraction × total pressure = 0.35 × 0.65 = 0.22 atm

6 0

3 years ago

3) (4.5 x 10-14) x (5.2 x 103) = ?

Otrada [13]

Answer:

16603.6

or

1.66036 x 10^4

Hope this helps! ^_^

4 0

3 years ago

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The two algae seen here are classified as green algae. That means they make their own food by photosynthesis. The algae on the l

ohaa [14]

Answer:

C

Explanation:

Unicellular algae can't do photosynthesis because it is a single cell organisms, therefore the answer is C

6 0

3 years ago

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When aqueous solutions of K3PO4 and Ba(NO3)2 are combined, Ba3(PO4)2 precipitates. Calculate the mass, in grams, of the Ba3(PO4)

Firdavs [7]

Answer:

Mass of Ba₃(PO₄)₂ = 0.0361 g

Explanation:

Given data:

Volume of Ba(NO₃)₂ = 1.2 mL (1.2 × 10⁻³ L )

Molarity of Ba(NO₃)₂ = 0.152 M

Volume of K₃PO₄ = 4.2 mL (4.2 × 10⁻³ L)

Molarity of K₃PO₄ = 0.604 M

Mass of Ba₃(PO₄)₂ produced = ?

Solution:

Chemical equation:

3Ba(NO₃)₂ + 2K₃PO₄ → Ba₃(PO₄)₂ + 6KNO₃

Number of moles of Ba(NO₃)₂ = Molarity × Volume in litter

Number of moles of Ba(NO₃)₂ = 0.152 M × 1.2 × 10⁻³ L

Number of moles of Ba(NO₃)₂ = 0.182 × 10⁻³ mol

Number of moles of K₃PO₄ = Molarity × Volume in litter

Number of moles of K₃PO₄ = 0.604 M × 4.2 × 10⁻³ L

Number of moles of K₃PO₄ = 2.537 × 10⁻³ mol

Now we will compare the moles of Ba₃(PO₄)₂ with K₃PO₄ and Ba(NO₃)₂ .

Ba(NO₃)₂ : Ba₃(PO₄)₂

3 : 1

0.182 × 10⁻³ : 1/3 ×0.182 × 10⁻³ = 0.060 × 10⁻³ mol

K₃PO₄ : Ba₃(PO₄)₂

2 : 1

2.537 × 10⁻³ : 1/2 × 2.537 × 10⁻³= 1.269 × 10⁻³ mol

The number of moles of Ba₃(PO₄)₂ produced by Ba(NO₃)₂ are less it will limiting reactant.

Mass of Ba₃(PO₄)₂ = moles × molar mass

Mass of Ba₃(PO₄)₂ = 0.060 × 10⁻³ mol × 601.93 g/mol

Mass of Ba₃(PO₄)₂ = 36.12 × 10⁻³ g

Mass of Ba₃(PO₄)₂ = 0.0361 g

6 0

3 years ago

Thermal energy is transferred from?

aliina [53]

Answer:

chemical and electrical ( and sometimes nucelar)

Explanation:

4 0

3 years ago

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