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ki77a [65]
3 years ago
6

Please help me I will give you the brain thing and extra points. 2

Chemistry
2 answers:
oee [108]3 years ago
7 0
I think it’s A but, don’t come at me if I’m wrong. Btw I read over it multiple times so this isn’t a random guess. Good luck tell me if you got it right
netineya [11]3 years ago
5 0
The answer is A pls give me brain thing
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sashaice [31]
I think it's DNA forms a double helix and RNA consists a single strand.
I may be wrong...
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3 years ago
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Answer now pls and i give you mega points ;)
astraxan [27]
HCl is an acid
C5H5N is a base
Cl- is a base
HC5H5N+ is an acid
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3 years ago
You burn a 15g jellybean to warm 50 mL of water, which increases the temperature of the water 25 °C. How many calories of heat a
Juli2301 [7.4K]

Answer:

Q = 375\,cal

Explanation:

The quantity of heat transfered from the jellybean to the water is:

Q = \rho\cdot V \cdot c\cdot \Delta T

Q = \left(1\,\frac{g}{cm^{3}}\right)\cdot (15\,cm^{3})\cdot \left(1\,\frac{cal}{g\cdot ^{\circ} C} \right)\cdot (25\,^{\circ}C )

Q = 375\,cal

7 0
3 years ago
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True or false water readily dissolves most polar compounds
morpeh [17]
The answer is false, I hope this helps.
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4 years ago
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A student carried out a titration using HC2H3O2(aq) and NaOH(aq). The net ionic equation for the neutralization reaction that oc
cluponka [151]

Answer:

The  ratio of HC2H3O2(aq) in the flask after the addition of 5.0mL of NaOH(aq) to HC2H3O2(aq) in the flask after the addition of 1.0mL of NaOH(aq) is 15 : 19 .

Explanation:

HC2H3O2 is  CH₃⁻ COOH, which is also known as Acetic acid.

IUPAC name of this compound is Ethanoic acid.

Acetic acid has a basicity of 1. so there is one acidic hydrogen is acetic acid.

Given that, equivalence point was reached when 20.0mL of NaOH is added.

let the normality of acetic acid is N₁ and that of NaOH is N₂.

    volume of acetic acid is V₁ and that of NaOH is V₂.  

 Equivalence point occurs when, N₁ × V₁ =  N₂ × V₂.

⇒  N₁ × V₁ =  N₂ × 20.

after the addition of 5.0mL of NaOH(aq), remaining N₁ × V°  = N₂ × (20 - 5).

                                                                                                  = N₂ × 15.

after the addition of 1.0mL of NaOH(aq), remaining N₁ × Vˣ = N₂ × (20 - 1).

                                                                                                  = N₂ × 19.

⇒ V° : Vˣ = 15 : 19 .

⇒

7 0
3 years ago
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