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3 years ago

Calculate the density in g/mL of:

1 answer:

5 0

Answer:

1st: 30/3=10g/mL
2nd: 23/30=.767g/mL

Explanation:

D=mass/volume, so when plugging the values into the equation, you should get these numbers.

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What are 3 examples of making diluted solutions in "regular" life? what are examples of diluted?

katrin [286]

Answer:

Do it your self bro

Explanation:

You lazy bum do it yourself

6 0

3 years ago

Ethane (CH) is one of many compounds that burns in oxygen to form carbon dioxide and water, as represented by the equation.

Nadya [2.5K]

Answer:

carbon dioxide and water.

Explanation:

Chemical equation:

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

Reactants are present on the left side of chemical equation while products are present on the right side of chemical equation. In given chemical equation ethane and oxygen are reactant while carbon dioxide and water are product.

The given reaction is combustion reaction. Ethane is burnt in the presence of oxygen and produces carbon dioxide and water.

The reaction also follow the law of conservation of mass.

This law was given by French chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

3 0

3 years ago

What is the formula weight of iron(II) sulfate? Answer in units of g/mol.

seropon [69]

Iron (II) sulfate also known as ferrous sulphate. Its chemical formula is FeSO₄, and formula weight is the sum of the atomic weights of all atoms that are present in a given chemical formula.

Molar mass of Fe is 55.8450 g/mol

Molar mass of S = 32.065 g/mol

Molar mass of oxygen = 15.999 g/mol

Now add the masses according to formula:

55.8450 + 32.065 + 4(15.999) = 151.96 is the formula weight of FeSO₄

3 0

3 years ago

Above the critical pressure, a substance is a(n) _____ fluid.

olga2289 [7]

The correct answer among the choices given is option C. Above the critical pressure, a substance is a supercritical fluid. This fluid is any substance at a temperature and pressure above the critical point here the phases of the liquid and the gas do not exist.

8 0

3 years ago

Read 2 more answers

The combustion of fuel in your car engine requires oxygen gas, which is supplied as air (21% oxygen molecules) into the engine.

miss Akunina [59]

Answer:

the maximum volume that can be burned per minute is: 0,895 mL of ethanol.

Explanation:

The combustion of ethanol is:

C₂H₅OH + 3 O₂ → 2 CO₂ + 3 H₂O

With gas law:

PV/RT = n

Where P is pressure (1,00 atm)

V is volume (4,73 L of air per minute)

R is gas constant (0,082 atmL/molK)

T is temperatue(25°C≡298,15K)

And n are moles, replacing:

n = 0,193 moles of air per minute.

These moles of air contain:

0,193 moles air × $\frac{21 molesO_2}{100 molesAIR}$ = 0,0406 moles O₂

Thus, the maximum volume that can be burned per minute is:

0,046 moles O₂ $\frac{1molC_{2}H_{5}OH}{3molesO_2} \frac{46,07 g}{1mol} \frac{1mL}{0,789g}$ = 0,895 mL of ethanol per minute

I hope it helps!

3 0

3 years ago