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Naya [18.7K]
4 years ago
13

Assignment: Waves Math Exploration

Chemistry
1 answer:
Svetach [21]4 years ago
5 0
Remember the formula for Wave Equation: Speed =  Wavelength x Frequency.

<span>1. What is the wave speed of a wave that has a frequency of 100 Hz and a wavelength of 0.30 m?
</span>S = 0.30 m x 100 Hz 
<span>S = 30 m/s

</span><span>2. What is the wave speed of a wave that has a frequency of 50 Hz and a wavelength of 0.10 m?
S = 0.10 m x 50 Hz
S = 5 m/s

</span><span>3. What is the frequency of a wave that has a wave speed of 20 m/s and a wavelength of 0.50 m?
F = 20 m/s / 0.50 m
F = 40 Hz

4. What is the frequency of a wave that has a wave speed of 80 m/s and a wavelength of 0.20 m?
F = 80 m/s / 0.20 m
F = 400 Hz

</span><span>5. What is the frequency of a wave that has a wave speed of 120 m/s and a wavelength of 0.40 m?
F = 120 m/s / 0.40 m
F = 300 Hz

6. What is the wavelength of a sound wave that has a speed of 340 m/s and a frequency of 440 Hz?
W = 340 m/s / 440 Hz
W = 0.77 m

7. What is the wavelength of a sound wave that has a speed of 340 m/s and a frequency of 880 Hz?
W = 340 m/s / 880 Hz
W = 0.39 m

8. What is the wavelength of a sound wave that has a speed of 250 m/s and a frequency of 400 Hz?
W =  250 m/s / 400 Hz
W = 0.63 m

9. What is the wave speed of a wave that has a frequency of 50 Hz and a wavelength of 2.0 m?
S = 2.0 m x 50 Hz
S = 100 m/s

10. What is the wave speed of a wave that has a frequency of 100 Hz and a wavelength of 0.50 m?
S = 0.50 m x 100 Hz
S = 50 m/s

Hope this helps. :)</span>
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The Equation of reaction

C + O2 === CO2

First Blank spot would be

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7 0
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Read 2 more answers
an ideal gas is at a pressure 1.00 x 10^5 N/m^2 and occupies a volume 11.00 m^3. If the gass is compressed to a volume of 1.00 m
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P_2=1.1x10^6Pa

Explanation:

Hello.

In this case, we can solve this problem by applying the Boyle's law which allows us to understand the pressure-volume behavior as a directly proportional relationship:

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P_2=\frac{1.00x10^5Pa*11.00m^3}{1.00m^3}\\ \\P_2=1.1x10^6Pa

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Regards.

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Answer:

See explanation

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