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ollegr [7]
1 year ago
12

N₂ + 3H2 → 2NH3

Chemistry
2 answers:
Ierofanga [76]1 year ago
5 0

ok this is a hard question i feel u

Explanation:

Rainbow [258]1 year ago
3 0

Answer:

187 moles NH₃

Explanation:

To find the amount of ammonia formed, you need to multiply the given value by the mole-to-mole ratio consisting of both relevant molecules. The mole-to-mole ratio is made up of the molecules' coefficients in the balanced equation. The desired unit should be placed in the numerator of the ratio. The final answer should have 3 sig figs to reflect the lowest amount of sig figs among the given values.

1 N₂ + 3 H₂ ----> 2 NH₃
^                         ^

93.5 moles N₂          2 moles NH₃
----------------------  x  -------------------------  =  187 moles NH₃
                                    1 mole N₂

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Answer:

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3 years ago
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Determine the equilibrium constant, Keq, at 25°C for the reaction
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Explanation:

The given chemical reaction is:

2Br^- (aq) + I_2(s)  Br_2(l) + 2I^- (aq)

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deltaG=-RTlnK_e_q\\delta=-nFE^o cell\\=>nFE^o cell=RTlnK_e_q\\lnK_e_q=\frac{nF}{RT} E^o cell

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Br- undergoes oxidation and I2 undergoes reduction.

Reduction takes place at cathode.

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Hence,

E^ocell= (-1.07+0.53)V\\=-0.54V

F=96485 C/mol

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ln K_e_q=\frac{2mol* 96485 C/mol}{8.314 J.K^-^1.mol^-^1x298K} \\\\lnK_e_q=77.8\\K_e_q=e^7^7^.^8\\=>K_e_q=6.13x10^3^3

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Keq=6.13x10^33

3 0
3 years ago
How many milliliters of a 0.40%(w/v) solution of nalorphine must be injected to obtain a dose of 1.5 mg?
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The number  of Ml  of  a  0.40 %w/v solution  of   ,nalorphine  that must  be injected  to  obtain  a  dose  of 1.5 mg is  calculated as  below


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