All categories

3 years ago

Find the lowest term 0.014 to 0.04

Mathematics

1 answer:

dolphi86 [110]3 years ago

7 0

Between the numbers 0.014 and 0.04, 0.014 is the lowest number because it amounts to less than 0.04.

You might be interested in

Using the formula below, calculate the z-score for the listed data points. z-score: zx = x − μ σ z1 = z5 = z6.5 =

wel

Answer:

z1 = -1.95

z5 = 0.05

z6.5 = 0.8

Step-by-step explanation: Good luck! :D

5 0

3 years ago

Read 2 more answers

PPLLZZ HELP ME IN THIS 2 QUESTIONS!

mestny [16]

1. The volume for prisim Q will be larger because the length is longer.

2. if the base is twice as large for prisim Q, the volume over all will be larger.

8 0

3 years ago

Vehicles leave an airport parking facility (arrive at parking fee collection booths) at a rate of 500 veh/h (the time between ar

Nutka1998 [239]

Answer:

At least 3 processing booths should be open.

Step-by-step explanation:

1 vehicle spends an average of 15 seconds in a booth

In N booths , there will be N/15 vehicles in 1 second

In 1 hr, there will be N/15 * 3600 vehicles

Therefore, there will be a total of 240N vehicles/hour

Actual arrival rate of vehicles at the airport is 500 veh/h

Probability of arrival, P = $\frac{Number of possible outcomes}{Total outcomes}$

P = 500/240N

P = 2.083/N

For the average time spends to be below 5 seconds

$\frac{(\frac{P^{2} }{1-p} )}{500} = 5$ , since 500 is the average value.

$\frac{P^{2} }{1-p} } = 2500\\P^{2} = 2500 (1-P)\\P^{2} = 2500 - 2500P\\(\frac{2.083}{N}) ^{2} = 2500 - 2500(\frac{2.083}{N})$

$2.083^{2} = 2500N^{2} - 5208N\\2500N^{2} - 5208N - 4.34 = 0$

$N^{2} -2.0832N - 0.0017 = 0$

Solving for N using the quadratic formula with a = 1, b = -2.0832, c = -0.0017

$N = \frac{-b \pm \sqrt{b^{2} -4ac} }{2a} \\N = \frac{2.0832 \pm \sqrt{(-2.0832)^{2} -4*1*(-0.0017)} }{2}$

N = 1.0416 ± 1.0424

N = 2.084 or -0.0008

N = 2.084 is the only realistic value here

Therefore, the smallest number of processing booths that must be open should be 3

5 0

3 years ago

Write an equation for the polynomial function that has 2 and -3 + 5i as zero

AysviL [449]

Answer:

$p(x) = {x}^{3} + 4{x}^{2} + 22x- 68$

Step-by-step explanation:

We want to write an equation for the polynomial function with roots;

$x = 2$

and

$x = - 3 + 5i$

Note that complex roots come in pairs and in conjugates.

Therefore

$x = - 3 - 5i$

is also a root.

By the factor theorem:

(x-2), (x+3+5i), and (x+3-5i) are factors of the polynomial.

Let p(x) be the polynomial, then in factored form.

$p(x) = (x - 2)(x + 3 + 5i)(x + 3 - 5i)$

We expand now to get:

$p(x) = (x - 2)( {x}^{2} + 3x - 5ix + 3x + 9 - 15i + 5ix + 15i + 25)$

Simplify now

$p(x) = (x - 2)( {x}^{2} + 6x +34)$

We expand further;

$p(x) = x( {x}^{2} + 6x + 34) - 2( {x}^{2} + 6x + 34)$

$p(x) = {x}^{3} + 6 {x}^{2} + 34x - 2 {x}^{2} - 12x - 68$

$p(x) = {x}^{3} + 4{x}^{2} + 22x- 68$

8 0

3 years ago

Find the value of each variable in the parallelogram.

Lorico [155]

Answer:

w = 2, z = 7

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask ;)

3 0

4 years ago