Answer:
The slope of the line that passes through points ( -10, -8 ) and ( -8, -16 ) is -4.
Explanation:
Points given = ( -10, -8) and ( -8, -16)
Slope = ?
( -10, -8 ) : x1 = -10 and y1 = -8
( -8, -16 ) : x2 = -8 and y2 = -16
We know,
slope = y2 - y1 / x2 - x1
Slope = -16 - ( -8) / -8 - (-10)
slope = -16 + 8 / -8 + 10
slope = -8 / 2
slope = -4
Therefore, slope of the line that passes through points ( -10, -8 ) and ( -8, -16 ) is -4.
Step-by-step explanation:
I believe that the answer is 1/5. I hope that this answer helps!<span />
- The Midpoint of AB is (1,0).
Given that:
- In line AB, where the coordinates of A is (3,1) and coordinates of B is (-1,-1).
To find:
So, according the question
We know that,
The midpoint M of a line segment AB with endpoints A (x₁, y₁) and B (x₂, y₂) has the coordinates M (
).
Now from question,
We know that the the coordinates of A is (3,1) and coordinates of B is (-1,-1) of line AB.
So, we can say that
A is (3,1) or x₁ = 3 and y₁ = 1.
B (-1,-1) or x₂ = -1 and y₂ = -1.
∵ The coordinates of midpoint M (X,Y)
X = 
= 
= 2/2
X = 1.
And
Y = 
= 
= 0/2
Y = 0.
So, the midpoint of line AB is M (1,0)
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The x is going to be a negative number to get the 3. so start off minus 5 from plus 5 and minus five from the other side too. the positive 5 and the negative cancel out and then take it fromt here with three and the negative 5.
You do kcf so 6/2/3 equal to 9