Tim mixed 2 parts vinegar and 5 parts water to make a cleaning liquid how many parts of vinegar did Tim mix with each part of wa
2 answers:
Answer: Tim mixed 0.4 parts of vinegar with each part of water.
Step-by-step explanation: Given that Tim mixed 2 parts vinegar and 5 parts water to make a cleaning liquid.
We are to find the number of parts of vinegar that Tim mix with each part of water.
We will be using the UNITARY method to solve the problem.
Number of parts of vinegar mix with 5 parts of water = 2.
Therefore, the number of parts of vinegar mix with 1 part of water i given by
Thus, Tim mixed 0.4 parts of vinegar with each part of water.
You might be interested in
Answer:
Hi there!
Recall that slope-intercept form is:
y = mx + b
Where m = slope
In this instance, we are given a slope of 4,
therefore:
y = 4x + b
Substitute in the x and y coordinates of the point given:
0 = 4(3) + b
0 = 12 + b
Substract 12 from both side:
-12 = b
Therefore, the equation would be:
y = 4x - 12
Graph the equation by finding x and y values or using a calculator:
x = 0, y = 4(0) - 12 = 12 (0, 12)
x = 1, y = 4(1) - 12 = - 8 (1, -8)
x = 2, y = 4(2) - 12 = - 4 (2, -4)
x = 3, y = 4(3) - 12 = 0 (3, 0)
And so forth:
Thanks<8
Answer: a) (0.755, 0.925)
Step-by-step explanation:
Let p be the population proportion of 8th graders are involved with some type of after school activity.
As per given , we have
n= 100
sample proportion:
Significance level :
Critical z-value : (using z-value table)
Then, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity will be :-
i.e.
i.e.
i.e.
Hence, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity : a) (0.755, 0.925)