Question

What charge is held by a 2.2 microfarad capacitor at a voltage of 6 V?

Answer 1

Answer:

Charge, $q=1.32\times 10^{-5}\ C$

Explanation:

It is given that,

Capacitance, $C=2.2\ \mu F=2.2\times 10^{-6}\ F$

Voltage, V = 6 volts

We need to find the charge held by the capacitor. It is given by :

$q=C\times V$

$q=2.2\times 10^{-6}\ F \times 6\ V$

q = 0.0000132 C

or

$q=1.32\times 10^{-5}\ C$

So, the charge held by the capacitor is $1.32\times 10^{-5}\ C$. Hence, this is the required solution.

Answer 2

Answer:

13.2\mu C

Explanation:

The capacitance of the capacitor C = 2.2 microfarad $=2.2\times 10^{-6}F$

Voltage at the capacitor =6 V

The charge on the capacitor is equal to the product of capacitance and the voltage , so charge = capacitance ×voltage

So charge $Q=CV=2.2\times 10^{-6}\times 6=13.2\times 10^{-6}C=13.2\mu C$