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aksik [14]
2 years ago
8

An object is moving east, and its velocity changes from 66 mvs to 26 mvs in 10 seconds. Which describes the

Physics
1 answer:
STALIN [3.7K]2 years ago
6 0

Answer:

negative acceleration of 4m/s²

Explanation:

Given parameters:

Initial velocity  = 66m/s

Final velocity = 26m/s

Time taken = 10s

Unknown:

Description of the acceleration  = ?

Solution:

Acceleration is the rate of change of velocity with time.

It is mathematically expressed as;

    acceleration  = \frac{v - u}{t}

v is the final velocity

u is the initial velocity

t is the time taken

  Now insert the parameters and solve;

    Acceleration  = \frac{26 - 66}{10}   = -4m/s²

So, we see a negative acceleration of 4m/s²

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A student wearing frictionless in-line skates on a horizontal surface is pushed, starting from rest, by a friend with a constant
grin007 [14]

Answer:

Physics

Explanation:

Explanation:

We can use the Theorem of Work (W) and Kinetic Energy (K):

W=ΔK=Kf−Ki

it basically tells us that the work done on our system will show up as change in Kinetic Energy:

We know that the initial Kinetic Energy, Ki=12mv2i, is zero (starting from rest) while the final will be equal to 352J; Work will be force time displacement. so we get:

F⋅d=Ff

45d=352

and so:

d=35245=7.8≈8m

8 0
2 years ago
Read 2 more answers
Calculate the acceleration of a train travelling from rest to 24 m/s in 12 seconds.
Vilka [71]
Answer: A 2m/s^2

Steps: Formula for acceleration. (Velocity Final - Initial Velocity) / Time

(24 - 0) / 12 = 2
3 0
2 years ago
One student did an experiment on the rock cycle.
Nonamiya [84]
First, when the student added the layers of wax over each other, this became a representation of sedimentary rocks.

Then the student folded his/her palm and squeezed the layers of wax. This means that the student applied heat and pressure on the wax (sedimentary rocks)

Referring to the diagram below which represents the rock cycle, we will find that applying heat and pressure on sedimentary rocks would convert these rocks into metamorphic rocks.

Based on the above, the best choice would be:
<span>d. Heat and pressure can change sedimentary rocks into metamorphic rocks.</span>

7 0
3 years ago
Consider an insulating sphere of radius 6 cm surrounded by a conducting sphere of inner radius 18 cm and outer radius 26 cm. Fur
dimulka [17.4K]

Answer:

-1.7908787542\times 10^{-9}\ C

3.4260289211\times 10^{-9}\ C

1.7908787542\times 10^{-9}\ C

1.6351501669\times 10^{-9}\ C

Explanation:

r = Radius

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

Electric field is given by

E=-\dfrac{kq}{r^2}\\\Rightarrow q=-\dfrac{Er^2}{k}\\\Rightarrow q=-\dfrac{1610\times 0.1^2}{8.99\times 10^9}\\\Rightarrow q=-1.7908787542\times 10^{-9}\ C

The charge is -1.7908787542\times 10^{-9}\ C

Q+q=\dfrac{Er^2}{k}\\\Rightarrow Q=\dfrac{Er^2}{k}-q\\\Rightarrow Q=\dfrac{120\times 0.35^2}{8.99\times 10^9}-(-1.7908787542\times 10^{-9})\\\Rightarrow Q=3.4260289211\times 10^{-9}\ C

The charge is 3.4260289211\times 10^{-9}\ C

The charge inside will have the polarity changed

q=+1.7908787542\times 10^{-9}\ C

Outside the charge will be

3.4260289211\times 10^{-9}-1.7908787542\times 10^{-9}\\ =1.6351501669\times 10^{-9}\ C

3 0
3 years ago
A small spinning asteroid is in a circular orbit around a star, much like the earth's motion around our sun. The asteroid has a
Fudgin [204]

Answer:

Temperature will be 305 K  

Explanation:

We have given The asteroid has a surface area A=7.70m^2

Power absorbed P = 3800 watt

Boltzmann constant \sigma =5.67\times 10^{-8}Wm/K^4

According to Boltzmann rule power radiated is given by

P=\sigma AT^4

3800=5.67\times 10^{-8}\times 7.70\times T^4

T^4=87.0381\times 10^8

T=305K

So temperature will be 305 K  

8 0
3 years ago
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