What is the final step in the fourth stage of technological design

A student buys a 5000 Btu window air conditioner for his apartment bedroom. He monitors it for one hour on a hot day and determi

pochemuha

Explanation:

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8 0

3 years ago

Explain why the radiative zone of the sun is hotter than the corona of the sun

dimulka [17.4K]

Answer: Because The spectra provided evidence to explain why the sun's atmosphere is so much hotter than its surface. ... Clear evidence now suggests that the heating mechanism depends on regular, but intermittent explosive bursts of heat, rather than on continuous gradual heating.

Explanation:

6 0

3 years ago

You launch a water balloon from the ground with a speed of 8.3 m/s at an angle of 27°. a. What is the horizontal component of th

solmaris [256]

a) The horizontal component of the velocity is 7.4 m/s

b) The vertical component of the velocity is 3.8 m/s

c) The balloon reaches the highest point after 0.39 s

d) The maximum height is 0.74 m

e) The total time of flight is 0.78 s

f) The range of the balloon is 5.77 m

Explanation:

a)

The motion of the balloon is the motion of a projectile, which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction

The horizontal component of the velocity (which is constant) is given by

$v_x = u cos \theta$

where

u = 8.3 m/s is the initial velocity of the balloon

$\theta=27^{\circ}$ is the angle of projection

Substituting,

$v_x = (8.3)(cos 27^{\circ})=7.4 m/s$

b)

The vertical component of the initial velocity of a projectile is given by

$u_y = u sin \theta$

where

u is the initial velocity

$\theta$ is the angle of projection

Here we have

u = 8.3 m/s

$\theta=27^{\circ}$

Substituting,

$u_y = (8.3)(sin 27^{\circ})=3.8 m/s$

c)

The vertical component of the velocity of the balloon follows the suvat equation

$v_y = u_y - gt$

where

$v_y$ is the vertical velocity at time t

$u_y = 3.8 m/s$ is the initial vertical velocity

$g=9.8 m/s^2$ is the acceleration of gravity

The balloon reaches the maximum height when the vertical velocity becomes zero:

$v_y = 0$

So we get:

$0=u_y -gt\\t=\frac{u_y}{g}=\frac{3.8}{9.8}=0.39 s$

d)

The maximum height of the balloon can be calculated using the suvat equation:

$s=u_y t - \frac{1}{2}gt^2$

where

$u_y = 3.8 m/s$ is the initial vertical velocity

$g=9.8 m/s^2$ is the acceleration of gravity

t = 0.39 s is the time at which the highest point is reached

Substituting,

$s=(3.8)(0.39)-\frac{1}{2}(9.8)(0.39)^2=0.74 m$

e)

The total time of flight of a projectile is twice the time needed to reach the maximum height, and it is given by

$t=\frac{2u_y}{g}$

where

$u_y$ is the initial vertical velocity

$g$ is the acceleration of gravity

Here we have

$u_y = 3.8 m/s$

$g=9.8 m/s^2$

Substituting,

$t=\frac{2(3.8)}{9.8}=0.78 s$

f)

The range of a projectile is the horizontal distance covered by the projectile, so it can be found by multiplying its horizontal velocity (which is constant) by the time of flight:

$d=v_x t$

where

$v_x$ is the horizontal velocity

t is the time of flight

Here we have

$v_x = 7.4 m/s$

$t = 0.78 s$

Substituting,

$d=(7.4)(0.78)=5.77 m$

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

7 0

3 years ago

It has been argued that power plants should make use of off-peak hours (such as late at night) to generate mechanical energy and

Trava [24]

Answer:

Explanation:

kinetic energy = 14.1 MJ = 14.1 x 10⁶ J

Let radius of flywheel be r .

volume of flywheel = π r² x t where t is thickness

= 3.14 x r² x .113 m³

= .04 r² m³

mass = volume x density

= .04 r² x 7800 = 312.73 r²kg

moment of inertia I = 1 / 2 mass x radius²

= .5 x 312.73 r² x r²

= 156.37 r⁴ kg m²

angular velocity ω = 2π x 93/60

= 9.734 rad /s

kinetic energy = 1/2 Iω² where ω is angular velocity

= .5 x 156.37 r⁴ x 9.734²

= 7408.08 r⁴

Given

7408.08 r⁴ = 14.1 x 10⁶

r⁴ = .19 x 10⁴

r = .66 x 10

= 6.60 m .

Diameter = 13.2 m

b )

centripetal acceleration of a point on its rim = ω² r

= 9.734² x 6.6

= 625.35 m /s²

5 0

3 years ago

What would happen if you use a thicker wire around the iron nail of an electromagnet? (thats the whole question)

puteri [66]

Answer:

When we have a current I, we will have a magnetic field perpendicular to this current.

Then if we have a wire in a "spring" form. then we will have a magnetic field along the center of this "spring".

Now suppose we put an iron object in the middle (where the magnetic field is) then we will magnetize the iron object.

Of course, the intensity of the magnetic field is proportional to the current, given by:

B = (μ*I)/(2*π*r)

Where:

μ is a constant, I is the current and r is the distance between to the current.

Now remember that for a resistor:

R = ρ*L/A

R is the resistance, ρ is the resistivity, which depends on the material of the wire, L is the length of the wire, and A is the cross-section of the wire.

If we increase the area of the wire (if we use a thicker wire).

And the relation between resistance and current is:

I = V/R

Where V is the voltaje.

Now, if we use a thicker wire, then the cross-section area of the wire increases.

Notice in the resistance equation, that the cross-section area is on the denominator, then if we increase the area A, the resistance decreases.

And the resistance is on the denominator of the current equation, then if we decrease R, the current increases.

If the current increases, the magnetic field increases, which means that we will have a stronger electromagnet.

3 0

3 years ago