Answer: If this population were in equilibrium and if the sickle-cell allele is recessive, the proportion of the population susceptible to sickle-cell anemia under typical conditions should be 0.20
Explanation: Hardy-Weinberg law provides an equation to relate genotype frequencies and allele frequencies in a randomly mating population. The equation is;
p² + 2pq + q² = 1
For 2 alleles such as A and a, where
p² = homozygous dominant
q² = homozygous recessive and
2pq = heterozygous
From the question, it is said that the sickle-cell allele (SS) constitutes 20% (that is, 20/100) of the hemoglobin alleles in the human gene pool and it is also said to be the homozygous recessive allele.
Therefore, q² = 20/100 = 0.20
Answer and Explanation:
A restriction enzyme is a type of endonuclease enzyme that recognizes a specific short nucleotide sequences on the DNA and cuts the DNA only at palindromic sites. There are different types of restriction enzymes:
1. Type I restriction enzyme – It cuts at sites far from the recognition site and requires both ATP and S-adenosyl- L-methionine as cofactor to function.
2. Type II restriction enzymes – It cleaves at short-specific distances from the recognition site and mostly requires magnesium to function.
3. Type III restriction enzymes – It recognizes two separate non-palindromic sites and cleaves at 20–30 base pairs away from a recognition site. It requires both ATP and S-adenosyl-L-methionine .
The restriction enzymes cleave DNA sequences producing either sticky or blunt ends that can be ligated with other sequences.
Conduits to transport the male gamete cells
