So we have a 6 at the bottom, and the root is 3, so hmm how to take it out, simple enough, just let's get something to make the 6 a 6³, so it comes out of the root
so
![\bf \cfrac{2+\sqrt[3]{3}}{\sqrt[3]{6}}\cdot \cfrac{\sqrt[3]{6^2}}{\sqrt[3]{6^2}}\implies \cfrac{(2+\sqrt[3]{3})(\sqrt[3]{6^2})}{(\sqrt[3]{6})(\sqrt[3]{6^2})}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{3}\cdot \sqrt[3]{36}}{\sqrt[3]{6^3}} \\\\\\ \cfrac{2\sqrt[3]{36}+\sqrt[3]{3\cdot 36}}{6}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{108}}{6}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{3^3\cdot 4}}{6} \\\\\\ \cfrac{2\sqrt[3]{36}+3\sqrt[3]{ 4}}{6}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B2%2B%5Csqrt%5B3%5D%7B3%7D%7D%7B%5Csqrt%5B3%5D%7B6%7D%7D%5Ccdot%20%5Ccfrac%7B%5Csqrt%5B3%5D%7B6%5E2%7D%7D%7B%5Csqrt%5B3%5D%7B6%5E2%7D%7D%5Cimplies%20%5Ccfrac%7B%282%2B%5Csqrt%5B3%5D%7B3%7D%29%28%5Csqrt%5B3%5D%7B6%5E2%7D%29%7D%7B%28%5Csqrt%5B3%5D%7B6%7D%29%28%5Csqrt%5B3%5D%7B6%5E2%7D%29%7D%5Cimplies%20%5Ccfrac%7B2%5Csqrt%5B3%5D%7B36%7D%2B%5Csqrt%5B3%5D%7B3%7D%5Ccdot%20%5Csqrt%5B3%5D%7B36%7D%7D%7B%5Csqrt%5B3%5D%7B6%5E3%7D%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B2%5Csqrt%5B3%5D%7B36%7D%2B%5Csqrt%5B3%5D%7B3%5Ccdot%2036%7D%7D%7B6%7D%5Cimplies%20%5Ccfrac%7B2%5Csqrt%5B3%5D%7B36%7D%2B%5Csqrt%5B3%5D%7B108%7D%7D%7B6%7D%5Cimplies%20%5Ccfrac%7B2%5Csqrt%5B3%5D%7B36%7D%2B%5Csqrt%5B3%5D%7B3%5E3%5Ccdot%204%7D%7D%7B6%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B2%5Csqrt%5B3%5D%7B36%7D%2B3%5Csqrt%5B3%5D%7B%204%7D%7D%7B6%7D)
That's two questions.
The answer to the second question is: Yes.
The answer to the first question is:
Multiply 60 miles per hour by ' 1 ' a few times. Use fractions that have
the same thing on top and bottom, since those are always equal to ' 1 '.
Then cancel units if the same unit is on the top and the bottom.
Here's how it goes:
(60 mi/hr) x (5280 ft/mile) x (1hr/3600 sec) = (60 x 5280 / 3600) ft/sec = <u>88 ft/sec</u>
Answer:
t(h)= (h-200)/-4.9
The time to reach a height of 50 meters is 30.6 seconds
Step-by-step explanation:
To express t as a function of height (h) we must transform the equation below:
h=200-4.9t
h-200=-4.9t
(h-200)/-4.9=t
t(h)= (h-200)/-4.9
To find the time to reach a height of 50 meters, we must replace this value on the new equation:
t(h)=50-200/-4.9
t(h)= 30.612
The time to reach a height of 50 meters is 30.6 seconds
Answer:
B - $41,500
Step-by-step explanation:
After Subtracting his liabilities this is what I got.
Hope this Helps!
:D
Answer:
In the last task, the result is 17+3x/6
Step-by-step explanation:
X+5/3 - 2x-7/6 + x/2
2(x+5)-(2x-7)+3x <em>/</em><em>6</em>
2x+10-2x+7+3x <em>/</em><em>6</em>
17+3x/6
I dunno this task above, I hope this one is correct :))
