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Oksana_A [137]
3 years ago
8

If the combined area of the white and orange regions is 100π, what is the area of ONLY the orange region?

Mathematics
2 answers:
7nadin3 [17]3 years ago
3 0
<span>64π</span><span> is correct, since the </span>area<span> of the white </span>circle<span> is 36</span>π, and 100π<span> - 36</span>π<span> = 64</span>π<span>.</span>
Sunny_sXe [5.5K]3 years ago
3 0
The area of orange=total-white

given
all=100pi

remember
area=pi times radius^2
white radius is 6
area=pi6^2
area=36pi

areaorange=areatotal-areawhite
areaorange=100pi-36pi
areaorange=64pi square units
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Need a little help here pls
Crank

Answer:

The statements that must be true are:

XY and JK form four right angles ⇒ B

XY ⊥ JK ⇒ C

JP = KP ⇒ E

m∠JPX = 90° ⇒ F

Step-by-step explanation:

From the given figure

∵ Line XY is the perpendicular bisector of the line segment JK

→ That means line XY is the line of symmetry of the line segment JK

∴ XY ⊥ JK ⇒ C

∵ XY ∩ JK at point P

∴ P is the midpoint of JK

∵ XY ⊥ JK

∴ ∠JPX, ∠KPX, ∠JPY, and ∠KPY are right angles

∴ XY and JK form four right angles ⇒ B

∵ The measure of the right angle is 90°

∴ m∠JPX = m∠KPX = m∠JPY = m∠KPY = 90°

∴ m∠JPX = 90° ⇒ F

∵ P is the midpoint of JK

∴ JP = KP ⇒ E

4 0
3 years ago
Can anyone help me solve this?​
Alecsey [184]

Answer:

Step-by-step explanation:

(\sqrt{z} +\sqrt{22})(\sqrt{z} -\sqrt{22})=35

Subtract both sides from 35

(\sqrt{z}+\sqrt{22} (\sqrt{z} -\sqrt{22})-35=35-35

Simplify:

(\sqrt{z})^{2} -57=0

Factor (\sqrt{z})^{2}  -57: (\sqrt{z}+\sqrt{57}) (\sqrt{z}-\sqrt{57})=0

\sqrt{z} +\sqrt{57}=0    or    \sqrt{z}  -\sqrt{57}=0

\sqrt{z} +\sqrt{57} =0: No Solution for Z

\sqrt{z} -\sqrt{57} =0: z=57

Your answer will be z=57

and No solution

8 0
2 years ago
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Simplify 3x²y³ over 12x⁶y
Svetllana [295]

Answer:

12x^6y

Step-by-step explanation:

7 0
3 years ago
Determine the measure of each numbered angle. Show work, provide a brief explanation. ​
monitta
Huhvgujvdthb friend gf t if y h iutzyreRx it’s g. Ttussuesru. G h
5 0
2 years ago
A) Let f(x) = 4x + 2 and g(x) = 2x^2-4. Find the formula for the composition function gof
ollegr [7]

Answer:

g o f = g(f(x)) = 32x^2 + 32x + 4

Step-by-step explanation:

Given

f(x) = 4x +2

g(x) =2x^2 - 4

Required:

Find g o f

This is calculated as:

gof = g(f(x))

g(x) =2x^2 - 4

So:

g(f(x)) = 2(4x+2)^2 - 4

g(f(x)) = 2(4x+2)(4x+2) - 4

g(f(x)) = 2[ 16x^2 + 16x + 4)] - 4

g(f(x)) = 32x^2 + 32x + 8 - 4

g(f(x)) = 32x^2 + 32x + 4

5 0
3 years ago
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