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11Alexandr11 [23.1K]
4 years ago
12

The wave shown below is produced in a rope.

Physics
2 answers:
Nutka1998 [239]4 years ago
7 0

Answer:

It is b

Explanation:

It’s not a the other comment is wrong.

Lena [83]4 years ago
6 0

Answer: B

Explanation:

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A force of 50 N stretches a string by 4 cm,calculate the elastic constant.
murzikaleks [220]

Answer:

50/0.04= answer

8 0
3 years ago
Ernie speed walks at the rate of 20m/s in 5 seconds. Calculate the distance he traveled
taurus [48]

Answer:

4m

Explanation:

you divide 20m/s by 5 seconds

7 0
3 years ago
A tank, shaped like a cone has height 12 meter and base radius 1 meter. It is placed so that the circular part is upward. It is
Temka [501]

Answer:

376966.991 Joules

Explanation:

Given that :

the height = 12  m

Let assume the tank have a thickness  = dh

The radius of the tank by using the concept of similar triangle is :

\dfrac{1}{r} = \dfrac{12}{h}

r = \dfrac{h}{12}

The area of the tank = \mathbf{\pi r^2}

The area of the tank = \mathbf{\pi( \dfrac{h}{12})^2}

The area of the tank = \mathbf{ \dfrac{\pi}{144}h^2}

The volume of the tank is  = area × thickness

= \mathbf{ \dfrac{\pi}{144}h^2 \  dh}

Weight of the element = \rho_ g * volume

where;

\rho_g = density of water ; which is given as 10000 N/m³

So;

Weight of the element = \mathbf{ 10000 *\dfrac{\pi}{144}h^2 \  dh}

Weight of the element = \mathbf{69.44 \ \pi  \ h^2 \  dh}

However; the work required to pump this water = weight × height  rise

where the height rise = 12 - h

the work required to pump this water  = \mathbf{69.44 \ \pi  \ h^2 \  dh}(12 - h)

the work required to pump this water  = \mathbf{69.44 \pi (12h^2-h^3)dh}

We can determine the total workdone by integrating the work required to pump this water

SO;

Workdone = \mathbf{\int\limits^{12}_0 {69.44 \pi(12h^2-h^3)} dh}

= \mathbf{ 69.44 \pi \int\limits^{12}_0 {(12h^2-h^3)} dh}

=  \mathbf{ 69.44 \pi[ \frac{12h^3}{3}-  \frac{h^4}{4}]^{12}}_0} }

= \mathbf{69.44 \pi [ \frac{12^4}{3}-\frac{12^4}{4}]}

= \mathbf{69.44 \pi*12^4 [ \frac{4-3}{12}]}

= \mathbf{69.44 \pi*12^4 *\frac{1}{12}}

= 376966.991 Joules

6 0
3 years ago
A gas cylinder has a volume of 0.4 m? It contains butane at a pressure of 100 kPa and a temperature of
morpeh [17]

The pressure needed : 800 kPa

<h3>Further explanation</h3>

Given

V₁ = 0.4 m³

P₁ = 100 kPa

T₁ = 20 + 273 = 293 K

V₂ = 0.05 m³

T₂ = T₁ = 293 K

Required

The final pressure(P₂)

Solution

Boyle's Law  

At a fixed temperature, the gas volume is inversely proportional to the pressure applied  

\tt \rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}

Input the value :

P₂=P₁V₁/V₂

P₂=100 x 0.4 / 0.05

P₂=800 kPa

4 0
3 years ago
How are Forensic reconstruction and archeological reconstruction different?
Genrish500 [490]

Answer:

การฟื้นฟูด้วยนิติเวช จะค้นหาเครื่องมือ การฟื้นฟู ด้วยปัจจุบันและอนาคต การฟื้นฟูด้วย โบราณคดี จะใช้ข้อมูลในอดีต

3 0
3 years ago
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