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3 years ago

Only refer from the community conservation article please. Will mark brainliest!!!!

Physics

1 answer:

Burka [1]3 years ago

3 0

And number 4. Is

the political actions that led to success conversation in the forest industry is What they call is a FC company that makes the forest industry true they make it out of a factory it can make it very successful and accomplished.

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Correctly label the various structures of the membranous labyrinth of the ear.

Ronch [10]

Answer:

left side top to bottom:

- saccule

- utricle

- ampullae

- semicircular duct: anterior

- semicircular duct: lateral

- semicircular duct: posterior

right side top to bottom:

- cochlear duct

- spiral ganglion of cochlea

- cochlear nerve

- vestibular nerve

7 0

3 years ago

Which of the following statements about diodes and triodes is correct

nata0808 [166]

There are no correct statements on your list.

4 0

3 years ago

Starting from rest, a small block of mass m slides frictionlessly down a circular wedge of mass M and radius R which is placed o

guapka [62]

Answer:

Part a)

$V = \sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}$

$v = \frac{M}{m}\sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}$

Part b)

Since on the block wedge system there is no external force in horizontal direction so the Center of mass will not move in horizontal direction but in vertical direction it will move

so displacement in Y direction is given as

$y_{cm} = \frac{mR}{m + M}$

Explanation:

PART A)

As we know that there is no external force on the system of two masses in horizontal direction

So here the two masses will have its momentum conserved in horizontal direction

So we have

$mv + MV = 0$

Also we know that here no friction force on the system so total energy will always remains conserved

So we have

$\frac{1}{2}mv^2 + \frac{1}{2}MV^2 = mgR$

now we have

$\frac{1}{2}m(\frac{MV}{m})^2 + \frac{1}{2}MV^2 = mgR$

$\frac{1}{2}MV^2(\frac{M}{m} + 1) = mgR$

so we have

$V = \sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}$

and another block has speed

$v = \frac{M}{m}\sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}$

Part b)

Since on the block wedge system there is no external force in horizontal direction so the Center of mass will not move in horizontal direction but in vertical direction it will move

so displacement in Y direction is given as

$y_{cm} = \frac{mR}{m + M}$

7 0

3 years ago

Froghopper insects have a typical mass of around 11.1 mg 11.1 mg and can jump to a height of 55.3 cm. 55.3 cm. The takeoff veloc

Molodets [167]

Answer:

a = 2710m/s²

Explanation:

See attachment below.