Answer:
Explanation:
T₁ = 700 + 273 = 973 k
T₂ = 330 + 273 = 603 k
Theoretical efficiency = T₁ - T₂ / T₁
= (973 - 603) / 973
= .38 OR 38%
Operating efficiency = .79 x 38
= 30.02 %
Heat input Q₁ , Heat output to sink Q₂ , conversion into power = Q₁ - Q₂
given Q₁ - Q₂ = 1.3 x 10⁹ W
efficiency = Q₁ - Q₂ / Q₁
Q₁ - Q₂ / Q₁ = 30.02 / 100
100Q₁ - 100Q₂ = 30.02Q₁
69.98 Q₁ = 100Q₂
Q₁ = 1.429 Q₂
Putting this in the relation
Q₁ - Q₂ = 1.3 x 10⁹ W
1.429Q₂ - Q₂ = 1.3 x 10⁹ W
.429Q₂ = 1.3 x 10⁹
Q₂ = 3.03 x 10⁹W
= 3.03 GW.
The answer would be the same amount. The system of car and earth is a roughly isolated system during the short time of acceleration (disregarding the rotation of the earth around its axis and its motion around the sun during this brief prompt). Therefore the net force on the system of car and road is zero, and the magnitude of alteration of momentum of both the car and the earth is the alike.
Answer:
Explanation:
The data we are given is:
V = ? fo = 100GHz fs = 100000015KHz C = 343m/s
With the doppler effect formula we can calculate the frequency perceived by the vehicle as:
(1)
Then, we sound waves bounce back on the vehicle:
(2) Replacing tha value obtained in (1)
Solving for V:
