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yaroslaw [1]
3 years ago
14

A force of 50 N stretches a string by 4 cm,calculate the elastic constant.

Physics
1 answer:
murzikaleks [220]3 years ago
8 0

Answer:

50/0.04= answer

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3 years ago
A steel cable has a cross-sectional area 4.49 × 10^-3 m^2 and is kept under a tension of 2.96 × 10^4 N. The density of steel is
Lemur [1.5K]

Answer:

The transverse wave will travel with a speed of 25.5 m/s along the cable.

Explanation:

let T = 2.96×10^4 N be the tension in in the steel cable, ρ  = 7860 kg/m^3 is the density of the steel and A = 4.49×10^-3 m^2 be the cross-sectional area of the cable.

then, if V is the volume of the cable:

ρ = m/V

m = ρ×V

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v = √(T×L/m)

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  = 25.5 m/s

Therefore, the transverse wave will travel with a speed of 25.5 m/s along the cable.

7 0
3 years ago
Which equations could be used as is, or rearranged to calculate for frequency of a wave? Check all that apply.
amm1812
-- Equations  #2  and  #6  are both the same equation,
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-- If you divide each side by  'wavelength', you get Equation #4,
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-- If you divide each side by  'frequency', you get Equation #3,
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Summary:

-- Equations #2, #3, #4, and #6 are all correct statements,
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-- Equations #1 and #5 are incorrect statements.
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