Answer:
(a) Jx = -1.14Ns, Jy = 110×3×10-³ = 0.330Ns (b) V = (0m/s)ı^−(1.79m/s)ȷ^
Explanation:
Given
W = 0.56N = mg
m = 0.56/g = 0.56/9.8 = 0.057kg
t = 3.00ms = 3.00×10-³s
Impulse is a vector quantity so we would treat it as such
We have been given the force and velocity in their component forms so to get the impulse from these quantities, we pick the respective component for the quantity we want to calculate and do the necessary calculation. The masses are scalar quantities and so do not affect the signs used in the calculations whether positive or negative. So we have that
u = (20.0m/s)ı^−(4.0m/s)ȷ^
ux = 20m/s
uy = – 4.0m/s
F = – (380N)ı^+(110N)ȷ^
Fx = –380N
Fy = 110N
J = impulse = force × time = F×t
So Jx = Fx ×t
Jy = Fy×t
Jx = –380×3×10-³ = -1.14Ns
Jy = 110×3×10-³ = 0.330Ns
Impulse also equals the change in momentum of the body. So
J = m(v–u)
J/m = v – u
V= J/m + u
Vx = Jx/m + ux
Vx = –1.14/0.057 + 20
Vx = -20 + 20 = 0m/s
Vx = 0m/s
Vy= Jy/m + uy
Vy= 0.33/0.057 + (-4.0)
Vy= 5.79 + (-4.0) = 1.79m/s
V = (0m/s)ı^−(1.79m/s)ȷ^
Answer:
a) Ffloor = 616.56[N]
b) Ffloor = 484.16 [N]
Explanation:
In order to solve this problem, we must first make a free body diagram. In this free body diagram include forces, as well as acceleration.
Then after the free body diagram, we perform a force analysis by means of Newton's second law, where the upward forces and even the upward acceleration will be taken as positive.
ΣF = m*a
where:
F = force [N] (units of Newtons]
m = mass [kg]
a = acceleration [m/s²]
g = gravity acceleration = 9,81 [m/s²]
a)
b) Using Newton's second law we have.
A=F/m
a=(3000000)/(20000)
a=15 m/s^2
Answer:
Juan's average speed is 2m/sec.
Explanation:
Since is formula for average speed is distance ÷ time, we can plug in our numbers.
100 = distance
50 seconds = time
100 ÷ 50 = 2
So, Juan's average speed is 2m/sec.
Hope this helps! Let me know if you have any other questions! :)