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4 years ago

5

A very fine thread is placed between two glass plates on one side and the other side is touching to form a wedge. A beam of mono

chromatic light of wavelength 600 nm illuminates the wedge and 178 bright fringes are observed. What is the thickness of the thread?

1 answer:

ki77a [65]4 years ago

4 0

Answer:

53.3micro meters

Explanation:

See attached file

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A women who normally weighs 400 N stands on top of a ladder so high she is one full additional earth radius above the surface of

AveGali [126]

The woman weighs 100N now.

Explanation:

Given:

F is given as 400N

one full additional earth radius formed

To Find:

Weight of the woman=?

Solution:

We know that gravitational force is inversely proportional to the square of radius.

$f_g=\frac{1}{r^2}$

where

$f_g$ is the gravitational force

$r^2$ is the radius square

So when radius is doubled, the force becomes one fourth of the original.

Therefore $\frac{1}{4} \times400 = 100N$

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3 years ago

A 25g rock is rolling at a speed of 5 m/s. What is the kinetic energy of the rock?

Mariulka [41]

Answer:

The answer is 312.5j

Explanation:

The kinetic energy (KE):

KE=1/2*m*v^2

M= mass of the object

v= velocity of the object

We have;

m=25g

v=5m/s

KE=1/2*25g*5^2m/s

KE =312.5j

6 0

3 years ago

Which statement about thin lenses is correct? In each case, we are considering only a single lens. A. A diverging lens always pr

Alexus [3.1K]

Answer:

E) true. The image is always virtual and erect

Explanation:

In this exercise we are asked to find the correct statements,

for this we can use the constructor equation

1 / f = 1 / p + 1 / q

where f is the focal length, p the distance to the object and q the distance to the image

In diverging lenses, the focal length is negative and the image is virtual and erect

In convergent lenses, the positive focal length, if the object is farther than the focal length, the image is real and inverted, and if the object is at a shorter distance than the focal length, the image is virtual and straight.

With this analysis let's review each statement

A) False. The image is right

B) False. The type of image depends on where the object is with respect to the focal length

C) False. The real image is always inverted

D) False. The image is always virtual

E) true. The image is always virtual and erect

6 0

3 years ago

For a demonstration, a professor uses a razor blade to cut a thin slit in a piece of aluminum foil. When she shines a laser poin

hoa [83]

Answer:

Slit width is 0.109 mm

Solution:

As per the question:

Wavelength of the light, $\lambda = 680\ nm = 680\times 10^{- 9}\ m$

Distance from the screen, D = 5.6 m

Bright band in the center, 2x = 8.1 cm

x = 4.05 cm

Now,

To calculate the slit width, w:

From the diffraction:

$sin\theta = \frac{\lambda}{w}$

For small angle:

$sin\theta$ ≈ $tan\theta = \frac{x}{D}$

Also

$\frac{x}{D} = \frac{\lambda }{w}$

Thus

$w = \frac{D}{x}\times \lambda$

Substituting appropriate values in the above eqn:

$w = \frac{6.5}{4.05\times 10^{-2}}\times 680\times 10^{- 9}$

w = 0.109 mm

7 0

4 years ago

Graphs help you see..

Diano4ka-milaya [45]

I think it's B because when you graph you do see the relationship between the dependent and independent variable

8 0

3 years ago