The particle's acceleration is 5.1 m/s²
<h3>
What is Acceleration ?</h3>
Acceleration can be defined as the rate at which velocity is changing. It is a vector quantity and it is measured in m/s²
Given that a particle is moving along a straight line with constant acceleration has a velocity of 2.35 m/s at t=3.42 s, and a velocity of -8.72 m/s at t=5.59s
The given parameters are;
Acceleration a = ΔV ÷ ΔT
a = (2.35 + 8.72) / (5.59 - 3.42)
a = 11.07 / 2.17
a = 5.1 m/s²
Therefore, the particle's acceleration is 5.1 m/s²
Learn more about Acceleration here: brainly.com/question/9069726
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Carbon dioxide
Helium
Argon
Hydrogen
Answer:
51.96 m/s^-1
Explanation:
a) see the attachment
b) As we know the velocity of the projectile has two component, horizontal velocity v_ox. and vertical velocity v_oy as shown in the figure. At the highest point of the trajectory, the projectile has only horizontal velocity and vertical velocity is zero. Therefore at the highest point of the trajectory, the velocity of the projectile will be
v_ox=v_o*cosФ
=60*cos (30)
= 51.96 m/s^-1
Answer:
C
Explanation:
Formula E=F/C also E=V/d
In this case use the second formula; E=V/d
Data given; E=4N/C d=8m
So v=E X d
V=4x8=32V
k.e=eV= 2X32=64eV