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3 years ago

5

A very fine thread is placed between two glass plates on one side and the other side is touching to form a wedge. A beam of mono

chromatic light of wavelength 600 nm illuminates the wedge and 178 bright fringes are observed. What is the thickness of the thread?

1 answer:

ki77a [65]3 years ago

4 0

Answer:

53.3micro meters

Explanation:

See attached file

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A proton is released in a uniform electric field, and it experiences an electric force of 2.36×10−14 N toward the south. (a)What

qwelly [4]

Answer:

a) E = 1.47 × 10^5 N/C

b) south

Explanation:

The magnitude of an electric field can be defined mathematically as;

E = F/q ........1

Where,

E = magnitude of the electric field

F = electric force

q = charge on the proton

Given;

F = 2.36 × 10^-14 N

Note that charge on a proton is known as Qp = 1.602 × 10^-19 C

q = 1.602 × 10^-19 C

Substituting into equation 1, we have;

E = 2.36 × 10^-14 N/1.602 × 10^-19 C

E = 1.47 × 10^5 N/C

b) The direction of the electric field;

From equation 1

E = F/q ........1

since both electric field and electric force are vector quantity and q is a positive charge (constant), then both the electric field and electric force would be parallel to each other. Therefore the electric field is directed to the south also.

(When a vector is multiplied by a positive constant the direction remains the same)

7 0

3 years ago

Water at 288.7 k flows through a 15.24-cm. diameter horizontal pipe into a 190-l drum. determine the minimum time it will take t

nikdorinn [45]

The flow will be laminar if Reynold's number $N_{R}$ is less than 2000.

Use the Reynold's formula and rearrange to calculate velocity of water in the pipe.

$N_{R} = \frac{v D}{\nu}$

Where, $v$ is velocity of the fluid, $D$ is the diameter of pipe, and $\nu$ is the kinematic viscosity i.e. $1.12 \times 10^{-6} m^2/s$ for water at 288.7 K from Appendix.

So, velocity is:

$v = \frac{N_{R} \nu}{D}$

The flow rate <em>Q</em>:

$Q = vA=v\pi D^2/4=\frac{\frac{N_R \nu}{D} \pi D^2}{4} =[tex] t = \frac{V}{\frac{N_R \nu \pi D}{4}} = \frac{4V}{N_R \nu \pi D} =\frac{4 \times 190 L\frac{10^{-3} m^3}{L}}{2000 \times 1.12\times 10^{-6} m^2/s \pi 15.24 cm\frac{1 m}{100 cm}} = 2226.3 s \frac{1 min}{60 s}= 37.1 min$ [/tex]

Where A is the area of cross section of pipe.

The time taken to fill is:

$t = Q/V$

Where V is the capacity of the tank.

7 0

3 years ago

Lead atoms occupy a volume of 3 x 10-29 m3. Each atom contributes two free electrons. Calculate the Fermi velocity of lead.

Juliette [100K]

<u>Answer:</u> The Fermi velocity of lead is 64.4 km/s.

<u>Explanation:</u>

To calculate the Fermi velocity, we use the equation:

$V_f=\frac{h}{2\pi m_e}(\frac{3\pi^2N}{V})^{1/3}$

where,

h = Planck's constant = $6.62\times 10^{-34}Js$

$m_e$ = mass of electron = $9.1\times 10^{-31}kg$

N = Number of atoms present in per volume of atom multiplied by number of electrons present in given atom = $\frac{2\times N_A\times V}{M}$

$N_A$ = Avogadro's number = $6.022\times 10^{26}mol^{-1}$ (When the mass is in kilograms)

V = Volume = $3\times 10^{-29}m^3$

M = molecular weight of lead = 207.2 g/mol

Putting values in above equation, we get:

$V_f=\frac{6.62\times 10^{-34}}{2\times 3.14\times (9.1\times 10^{-31})}(\frac{3\times (3.14)^2\times (2\times 6.022\times 10^{23}\times 3\times 10^{-29})}{3\times 10^{-29}\times 207.2})^{1/3}$

$V_f=0.0644\times 10^6m/s=64.4km/s$ (Conversion factor: 1 km = 1000 m)

Hence, the Fermi velocity of lead is 64.4 km/s

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3 years ago

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Answer:

decantation, distilling, freezing

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3 years ago

What are three sports that use force (EXCEPT FOOTBALL)

Anika [276]

Soccer, golf, baseball

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2 years ago