Answer:
(a) 43.2 kC
(b) 0.012V kWh
(c) 0.108V cents
Explanation:
<u>Given:</u>
- i = current flow = 3 A
- t = time interval for which the current flow =

- V = terminal voltage of the battery
- R = rate of energy = 9 cents/kWh
<u>Assume:</u>
- Q = charge transported as a result of charging
- E = energy expended
- C = cost of charging
Part (a):
We know that the charge flow rate is the electric current flow through a wire.

Hence, 43.2 kC of charge is transported as a result of charging.
Part (b):
We know the electrical energy dissipated due to current flow across a voltage drop for a time interval is given by:

Hence, 0.012V kWh is expended in charging the battery.
Part (c):
We know that the energy cost is equal to the product of energy expended and the rate of energy.

Hence, 0.108V cents is the charging cost of the battery.
Answer:
C to/tc
Explanation:
This is just the reason for this question
This one is easy :) it is called a "Hypothesis"!
Answer:
a) 0.94 C
b) 7.14 m
c) 3.11 m
d) 1.40 s
e) 2.93 s
Explanation:
First we need to set up a coordinate system. This will have the positive X axis pointing north. So spaceship A has positive speed, and spaceship B has negative speed.
The Lorentz transformation for speed is:

u: speed of spaceship A as observed by you
v: speed of spaceship B as observed by you
In the case of the speed of spaceship A as observed by spaceship B:

The transform for lengths is:

For the case of spaceship A as observed by you:

For the case of spaceship A as observed by spaceship B:

The time dilation equation is:

For the case of the event as observed by you:

For the case of the event as observed by spaceship B:
