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Vlad1618 [11]
3 years ago
11

A 4kg block sitting on the floor, how much potential energy does it have?

Physics
2 answers:
aniked [119]3 years ago
8 0
P.E.=mgh

P.E.= mass×gravity×height, therefore 4kg×10×0= 0 J

K.E. is also equal to 0 because the block is not moving, is in the state of Inertia
prohojiy [21]3 years ago
3 0

Well, there you have a very important principle wrapped up in that question.

There's actually no such thing as a real, actual amount of potential energy.
There's only potential <em><u>relative to some place</u></em>.  It's the work you have to do
to lift the object from that reference place to wherever it is now.  It's also
the kinetic energy the object would have if it fell down to the reference place
from where it is now.

Here's the formula for potential energy:    PE = (mass) x (gravity) x (<em><u>height</u></em><u>)</u> .

So naturally, when you use that formula, you need to decide "height above what ?"

If you're reading a book while you're flying in a passenger jet, the book's PE is
(M x G x 0 meters) relative to your lap, (M x G x 1 meter) relative to the floor of the
plane, (M x G x 10,000 meters) relative to the ground, and maybe (M x G x 25,000 meters)
relative to the bottom of the ocean.

Let's say that gravity is 9.8 m/s² .

Then a 4kg block sitting on the floor has (39.2 x 0 meters) PE relative to the floor
it's sitting on, also (39.2 x 3 meters) relative to the floor that's one floor downstairs,
also (39.2 x 30 meters) relative to 10 floors downstairs, and if it's on the top floor of
the Amoco/Aon Center in Chicago, maybe (39.2 x 345 meters) relative to the floor
in the coffee shop that's off the lobby on the ground floor. 

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To solve this problem it is necessary to apply the concepts related to wavelength depending on the frequency and speed. Mathematically, the wavelength can be expressed as

\lambda = \frac{v}{f}

Where,

v = Velocity

f = Frequency,

Our values are given as

L = 3.6m

v= 192m/s

f= 320Hz

Replacing we have that

\lambda = \frac{192}{320}

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N = \frac{L}{\lambda}

N = \frac{3.6}{0.6}

N = 6

Therefore the number of wavelengths of the wave fit on the string is 6.

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3 years ago
A car slams on its breaks,producing friction between the tires and the road.Into which type of energy is the mechanical energy o
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The answer is Heat Energy
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. A spring has a length of 0.200 m when a 0.300-kg mass hangs from it, and a length of 0.750 m when a 1.95-kg mass hangs from it
kap26 [50]

Answer:

29.4 N/m

0.1  

Explanation:

a) From the restoring Force we know that :  

F_r = —k*x  

the gravitational force :  

F_g=mg  

Where:

F_r is the restoring force .

F_g is the gravitational force

g is the acceleration of gravity

k is the constant force  

xi , x2 are the displacement made by the two masses.

Givens:

<em>m1 = 1.29 kg</em>

<em>m2 = 0.3 kg  </em>

<em>x1   = -0.75 m  </em>

<em>x2 = -0.2 m </em>

<em>g   = 9.8 m/s^2  </em>

Plugging known information to get :

F_r =F_g

-k*x1 + k*x2=m1*g-m2*g

k=29.4 N/m

b) To get the unloaded length 1:  

l=x1-(F_1/k)

Givens:

m1 = 1.95kg , x1 = —0.75m  

Plugging known infromation to get :

l= x1 — (F_1/k)  

= 0.1  

 

3 0
3 years ago
What is the difference between an open and closed circuit?
exis [7]
A closed circle means the number is included and an open circle means its not.
7 0
3 years ago
If the distance between the levers input force and the fulcrum is 8 cm, and the distance between the fulcrum and the output forc
ololo11 [35]

Answer:

Ideal mechanical advantage of the lever is 3.

Explanation:

Given that,

The distance between the levers input force and the fulcrum is 8 cm, d_i=8\ cm

The distance between the fulcrum and the output force is 24 cm, d_o=24\ cm

To find,

The ideal mechanical advantage of the lever.

Solution,

The ratio of the distance between the fulcrum and the output force to the distance between the levers input force and the fulcrum is called the ideal mechanical advantage of the lever. It is given by :

m=\dfrac{d_o}{d_i}

m=\dfrac{24}{8}

m = 3

So, the ideal mechanical advantage of the lever is 3.

5 0
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