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Katyanochek1 [597]
3 years ago
14

What are the roots of the equation

id="TexFormula1" title=" {x}^{2} - 16x + 89 = 0" alt=" {x}^{2} - 16x + 89 = 0" align="absmiddle" class="latex-formula">
in simplest a+bi form?
Mathematics
1 answer:
densk [106]3 years ago
3 0

By completing the square,

x^2-16x+89=x^2-16x+64+25=(x-8)^2+25=0

(x-8)^2=-25

x-8=\pm\sqrt{-25}

x=8\pm5i

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</span>In Step 1, Hannah wrote \dfrac{d}{dx} (-3+8x) <span> as the sum of two separate derivatives </span>\dfrac{d}{dx}(-3)+ \dfrac{d}{dx} (8x) <span>using the </span><span>sum rule.
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