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Lelechka [254]
4 years ago
9

What is 121 increased to 321???

Mathematics
2 answers:
pentagon [3]4 years ago
8 0
121+321=442 hope I helped

Katarina [22]4 years ago
4 0
Number increased = 321 - 121 = 200

Percentage increased, 200/121 * 100 = 165.29%

Hope this helps!
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At some moment in time, a culture of bacteria contains 100 bacteria. After one hour, there are 300
LenKa [72]

Answer:

i think its a if im wrong im sorry

Step-by-step explanation:

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3 years ago
On February 11, the temperature was -4 Degrees F in Denver,and in Miami the temperature was 65 Degrees F. How much warmer was it
kow [346]

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This is because there is a negative and a positive number so you subtract and you get a positive number because In the equation the positive number is larger.

6 0
3 years ago
I need major help pretty pls this so different
crimeas [40]
First put a bubble around 5x-7. Now you plug that into the problem. -3x-2
(5x-7)=12. now times the -2 by 5x which is -10x. and then times the -2 by -7 which is 14. so now you have -3x-10x+14=-12. add the -3x and -10x. -13x. Add the 14 over. -13x=2. Now dived by -13, which gives us x=-0.15

Now you take that a plug it into the -3x-2y=-12. So that it looks like this -3(-0.15)-2y=-12

Now times the -3 by -0.15 to give us 20 -2y=-12.   Now 'kill' the 20, so that it looks like this -2y=-32. Now you divide by -2 and get y=16. 

Now your ordered pair is (-0.15,16)
7 0
3 years ago
Your parents offer you 50%<br> interest every day if you<br> invest your 4 dollars with<br> them.
N76 [4]

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b

Step-by-step explanation:

                                                     

6 0
3 years ago
Find the sum of the first 8 terms of the series. 1/2 + 1 + 2 + 4
Roman55 [17]

\bf \cfrac{1}{2}~~,~~\stackrel{2\cdot \frac{1}{2}}{1}~~,~~\stackrel{2\cdot 1}{2}~~,~~\stackrel{2\cdot 2}{4}~~,...

so as you can see the common ratio is 2, and the first term is 1/2,

\bf \qquad \qquad \textit{sum of a finite geometric sequence} \\\\ S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad  \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ r=\textit{common ratio}\\ ----------\\ r=2\\ a_1=\frac{1}{2}\\ n=8 \end{cases} \\\\\\ S_8=\cfrac{1}{2}\left( \cfrac{1-2^8}{1-2} \right)\implies S_8=\cfrac{1}{2}\left( \cfrac{-255}{-1} \right)\implies S_8=\cfrac{255}{2}

4 0
4 years ago
Read 2 more answers
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