Question

If x+y=7/13 and x-y=1/91, what is the value of x²-y²? Express your answer as a common fraction.

Answer 1

Answer:

$\frac{1}{169}$

Step-by-step explanation:

It is given:

$x+y=\frac{7}{13}$

and

$x-y=\frac{1}{91}$

We are asked to find the value of "$x^2-y^2$"

We remember a rule/formula from algebra:

$x^2-y^2=(x+y)(x-y)$

Using this formula we can write:

$x^2-y^2=(x+y)(x-y)=(\frac{7}{13})(\frac{1}{91})=\frac{1}{13}*\frac{1}{13}=\frac{1}{169}$

The answer is:

$\frac{1}{169}$