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Tems11 [23]
3 years ago
9

Question 1: Find the distance between the points (1, 4) and (5, 1).

Mathematics
2 answers:
Anit [1.1K]3 years ago
6 0

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(5-1)^2+(1-4)^2}\implies d=\sqrt{4^2+(-3)^2} \\\\\\ d=\sqrt{16+9}\implies d=\sqrt{25}\implies d=5

Xelga [282]3 years ago
4 0

Answer: second option.

Step-by-step explanation:

You need to use the formula for calculate the distance between two points. This is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Given the point (1, 4) and the point (5, 1), you can say that:

x_2=5\\x_1=1\\y_2=1\\y_1=4

Now you must substitute these values into the formula.

The distance between the points (1, 4) and (5, 1) is the following:

d=\sqrt{(5-1)^2+(1-4)^2}\\\\d=5

This matches with the second option.

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19,432÷x=48 Remainder 232 (Plz help its for my hw that's due tmrw)
Neko [114]

Answer:

x = 404.83

Step-by-step explanation:

The given expression is :

19,432÷x=48 ...(1)

We need to find the value of x.

\dfrac{19,432}{x}=48

Cross multiplying both sides,

19,432=48x

Dividing both sides by 48

\dfrac{19,432}{48}=x\\\\x=404.83

So, the value of x is 404.83.

4 0
2 years ago
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|3x-4| +2=1<br> Please help!
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3 years ago
Y=-2(x-3)^2 +10<br> Y=4x
shepuryov [24]

Answer:

i might be wrong but 8 if not (2,8) if not sorry

Step-by-step explanation:

7 0
3 years ago
7. Which of the following best presents the graph of a line with a slope of -2/3 and a y-intercept of -1?
Sonja [21]
The correct graph would be graph A.

Since the line hits the y-axis at -1. And it goes down 2 and to the left 3 for each point.
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3 years ago
PLEASE HELP WITH 1-3 ILL MARK U THE BRAINLIEST
sammy [17]

Answer:

1:A(-6,-1) B(-14,0) C(-11,4)

2:D(6,-3) E(2,-3) F(3, -4.5) G(5, -4.5)

3:H(-4,1) I(-4, 6) J(0,6) K(0,1)

Step-by-step explanation:

Before we begin, lets define the transformations:

(x, y)

T(a, b) = (x+a, y +b)

Rxaxis = (x, -y)

Ryaxis = (-x, y)

r(180, 0) = (-x, -y)

D.5(1/2x, 1/2y)

R(-90, O) = (-y, x)

1. T. A(6,-1) B(14,0) C(11,4)

   Rx. A(6, 1) B(14,0) C(11,-4)

   r180 A(-6,-1) B(-14,0) C(-11,4)

2. Rx D(-12,-6) E(-4,-6) F(-6, -9) G(-10, -9)

   Ry D(12,-6) E(4,-6) F(6, -9) G(10, -9)

   D.5 D(6,-3) E(2,-3) F(3, -4.5) G(5, -4.5)

3. Rx=1 H(-1,2) I(4, 2) J(4,-2) K(-1,-2)

   T H(1,4) I(6, 4) J(6,0) K(1,0)

   r-90 H(-4,1) I(-4, 6) J(0,6) K(0,1)

4 0
3 years ago
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