1- 3/4
2- 64
3- 18
4- 36
5- 10
6- 3/4
7- $4.70
8- <
9- =
10- =
<span>, y+2 = (x^2/2) - 2sin(y)
so we are taking the derivative y in respect to x so we have
dy/dx use chain rule on y
so y' = 2x/2 - 2cos(y)*y'
</span><span>Now rearrange it to solve for y'
y' = 2x/2 - 2cos(y)*y'
0 = x - 2cos(y)y' - y'
- x = 2cos(y)y' - y'
-x = y'(2cos(y) - 1)
-x/(2cos(y) - 1) = y'
</span><span>we know when f(2) = 0 so thus y = 0
so when
f'(2) = -2/(2cos(0)-1)
</span><span>2/2 = 1
</span><span>f'(2) = -2/(2cos(0)-1)
cos(0) = 1
thus
f'(2) = -2/(2(1)-1)
= -2/-1
= 2
f'(2) = 2
</span>
Volume of the box is 204 in³
<u>Step-by-step explanation:</u>
Step 1:
Volume of the box = length × width × height
Length = 10 2/3 = 32/3 in,
width = 3 in and height = 6 3/8 = 51/8 in
⇒ Volume = 32/3 × 3 × 51/8 = 4 × 51 = 204 in³