<em>Rounded to the nearest tenth of an inch the Witdth of the monitor is 14.8 inches while the Height of the monitor is 11.9 inches.</em>
<h2>
Explanation:</h2><h2 />
The aspect ratio is defined as:
<em>"The proportional relationship between the width and height of an image"</em>
It is usually expressed in a mathematical language as:

So, it is true that:

In this case, we know that the monitor has a diagonal length (D):

So, by Pythagorean theorem:


Finding x:

<em>Finally, rounded to the nearest tenth of an inch the Witdth of the monitor is 14.8 inches while the Height of the monitor is 11.9 inches.</em>
<h2>
Learn more:</h2>
Pythagorean Theorem: brainly.com/question/10182890
#LearnWithBrainly
Basically, all you have to do is substitue the terms given at the top.
x = -3
y = 6
z = -4
<em>The first one will be set up like this:</em>
(-3) + 6 + (-1) = 2
<em>The second one will be set up like this: </em>
-15 + (- -3) + 6 = -6
<em>The third one will be set up like this:</em>
3(-3) - 2(6) + (-4) = -25
<em>The fourth one will be set up like this:</em>
2(-4) - 3 (6) + 4(-3) = -38
<em>The fifth one will be set up like this: </em>
3 ( -3) + 2 (6) + (-4) = -1
<em>The sixth will be set up like this: </em>
(-3)(-4)
---------- = -1
-2 (6)
<em>The seventh will be set up like this:</em>
2 (6) (-4) - 3 (-3) = -39
Hope this helps! Have a good day/night! c:
Answer:
<h2><u>E</u><u>k</u>sponent</h2>
![\sf{ \large{ \boxed{ \red{ {a}^{ \frac{n}{m} } = \sqrt[m]{ {a}^{n} } } } }}](https://tex.z-dn.net/?f=%20%20%5Csf%7B%20%5Clarge%7B%20%5Cboxed%7B%20%5Cred%7B%20%7Ba%7D%5E%7B%20%5Cfrac%7Bn%7D%7Bm%7D%20%20%7D%20%20%3D%20%20%5Csqrt%5Bm%5D%7B%20%7Ba%7D%5E%7Bn%7D%20%7D%20%7D%20%7D%20%7D%7D)

![= \sqrt[3]{ {2}^{4} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%5B3%5D%7B%20%7B2%7D%5E%7B4%7D%20%7D%20)
![= \sqrt[3]{2 \times 2 \times 2 \times 2}](https://tex.z-dn.net/?f=%20%3D%20%20%20%5Csqrt%5B3%5D%7B2%20%5Ctimes%202%20%5Ctimes%202%20%5Ctimes%202%7D%20)
![= \boxed {\bold{\sqrt[3]{16}(c.) }}](https://tex.z-dn.net/?f=%20%3D%20%20%20%5Cboxed%20%20%7B%5Cbold%7B%5Csqrt%5B3%5D%7B16%7D%28c.%29%20%7D%7D)
-6+3-3(-18)
Okay.
Work from left to right.
-6 plus 3 equals -3.
(Think of it as in a number line, from the spot of -6, move right three units. This will give you -3. Anyways..)
Now you have -3-3
The result is -6.
-6(-18)
Negative six times negative eighteen equals positive 108.
The answer is 108.
(Sorry for the long reply)
Answer:
PQR and JK
Step-by-step explanation:
ΔGHJ ≈ ΔPQR by the Transitive Property of Congruence. GH ≈ JK since corresponding parts of congruent figures are congruent.
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