3 years ago

Find tan v for the traingle

Mathematics

1 answer:

ella [17]3 years ago

8 0

Answer:

Step-by-step explanation:

tan V = $\frac{opposite}{adjacent}$ = $\frac{UT}{UV}$ = $\frac{8}{15}$ → C

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Lunna [17]

$-\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|-\frac{2}{3}-2^3-\frac{2}{3}\left|-\frac{1}{2}\right|^3$
$\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|=\frac{1}{12}$
$\frac{2}{3}\left|-\frac{1}{2}\right|^3=\frac{1}{12}$
$=-\frac{1}{12}-\frac{2}{3}-2^3-\frac{1}{12}$
$=-\frac{53}{6}$

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3 years ago

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Step-by-step explanation: