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Papessa [141]
3 years ago
9

Ask me a question. any question. ill probably answer it. unless I'm lazy.

Mathematics
1 answer:
ipn [44]3 years ago
6 0

Answer:

What is your fav artist music wise

Step-by-step explanation:

You might be interested in
Which number is not in scientific notation?
Hitman42 [59]

Answer:

A 9 ⋅ 1019

B 7.8 ⋅ 106

C 1.45 ⋅ 10−7

D 0.33 ⋅ 10−15

Step-by-step explanation:

A 9 ⋅ 1019

B 7.8 ⋅ 106

C 1.45 ⋅ 10−7

D 0.33 ⋅ 10−15

6 0
3 years ago
PLEASE HELP ASAP!! WILL GIVE BRAINLIEST AND 30 POINTS!! SOLVE FOR VALUE OF X. PLEASE EXPLAIN HOW YOH GO THE ANSWER OR HOW YOU SO
Serhud [2]

Answer: x=3

I got to the answer by doing simple math. Both sides must be even.

5x-4

5(3)-4= 15-4 = 11

x+8

3+8= 11

So x=3

7 0
3 years ago
Atul has 2/3 lb of candy. Jose has 3/5 lb and Maria has 1/2 lb less then José. How many more pounds of candy does Atul have than
liraira [26]

Given:

Atul has \dfrac{2}{3} lb of candy.

Jose has \dfrac{3}{5} lb of candy.

Maria has \dfrac{1}{2} lb less than Jose.

To find:

How many more pounds of candy does Atul have than Maria?

Solution:

Since, Maria has \dfrac{1}{2} lb less than Jose, therefore

Maria has = \dfrac{3}{5}-\dfrac{1}{2} lb

Maria has = \dfrac{6-5}{10} lb

Maria has = \dfrac{1}{10} lb

Difference between the candies Atul and Maria have.

Difference = \dfrac{2}{3}-\dfrac{1}{10} lb

Difference = \dfrac{20-3}{30} lb

Difference = \dfrac{17}{30} lb

Therefore,  Atul have \dfrac{17}{30} lb of candy more than Maria.

6 0
3 years ago
Help please! ty sm. image attached below
Bond [772]

Answer:

its 5

Step-by-step explanation:

it's in between them

6 0
3 years ago
How many solutions does the absolute value equation below have?<br><br><br><br><br><br> |x + 6| = –8
WINSTONCH [101]
The answer is there are no solution that fulfill this equation because if you put for example -14 the answer will be -8 but there is absolutely sign, so the answer is 8. Hope it help!
6 0
3 years ago
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