Answer:
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Step-by-step explanation:
So we are given the mean and the s.d.. The mean is 100 and the sd is 15 and we are trying the select a random person who has an I.Q. of over 126. So our first step is to use our z-score equation:
z = x - mean/s.d.
where x is our I.Q. we are looking for
So we plug in our numbers and we get:
126-100/15 = 1.73333
Next we look at our z-score table for our P-value and I got 0.9582
Since we are looking for a person who has an I.Q. higher than 126, we do 1 - P. So we get
1 - 0.9582 = 0.0418
Since they are asking for the probability, we multiply our P-value by 100, and we get
0.0418 * 100 = 4.18%
And our answer is
4.18% that a randomly selected person has an I.Q. above 126
Hopes this helps!
Answer:
D. Associative Property
Step-by-step explanation:
The group is being switched around.
Answer:
<h2><u><em>30x² − 23x − 14</em></u></h2>
Explanation:
Length: (6x - 7)
Width: (5x + 2)
(6x - 7) (5x + 2)
= (6x + −7)(5x + 2)
(6x)(5x) + (6x)(2) + (−7)(5x) + (−7)(2)
= 30x² + 12x − 35x − 14
- PNW
