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3 years ago

What is 8 1/2 divided by 5 2/3

Mathematics

2 answers:

Nadusha1986 [10]3 years ago

7 0

This is what i got in picture form

amm18123 years ago

3 0

<span>8 1/2 divided by 5 2/3 is </span>1 1/2

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Help please rn help

aksik [14]

Area of the large semicircle

$= \pi{r}^{2} \div 2$

$= \frac{22}{7} \times 12 {}^{2} \times \frac{1}{2}$

$= \frac{11}{7} \times12 \times 12$

$= \frac{11}{7} \times 144$

$= 226.28$

Area of the small semicircle

$= \pi {r}^{2} \div 2$

$= \frac{22}{7} \times 6 {}^{2} \times \frac{1}{2}$

$= \frac{11}{7} \times 6 \times 6$

$= \frac{11}{7} \times 36$

$= 56.57$

Area of the figure

$= 226.28 - 56.57$

$= 169.71 {cm}^{2}$

8 0

3 years ago

There are 38 cars parked in the parking structure. The parking structure is not full of capacity. There are 13 parking spaces th

Lynna [10]

Answer:

$\frac{13}{38}$ or $13:38$ .

Step-by-step explanation:

We have been given that there are 38 cars parked in the parking structure. There are 13 parking spaces that are empty. We are asked to find the ratio of available parking spaces to parked cars.

To find the ratio of available parking spaces to parked cars, we will set an equation as:

$\frac{\text{Available Parking space}}{\text{Parked cars}}=\frac{13}{38}$

Therefore, the ratio of available parking spaces to parked cars is $\frac{13}{38}$ or $13:38$ .

8 0

3 years ago

Use the table of integrals, or a computer or calculator with symbolic integration capabilities, to find the indefinite integral.

andriy [413]

Answer:

$\frac{2}{3}(\frac{1}{5}ln|3x-5|-\frac{1}{5}ln|x|)+C$

Step-by-step explanation:

We have been given a indefinite integral $\int \frac{2}{3x\left(3x-5\right)}dx$ . We are asked to find the indefinite integral.

We will use partial fraction formula to solve our given problem.

$\frac{2}{3x\left(3x-5\right)}=\frac{3}{5(3x-5)}-\frac{1}{5x}$

$\int \frac{2}{3x\left(3x-5\right)}dx=\frac{2}{3}\int \frac{1}{x\left(3x-5\right)}dx$

$\frac{2}{3}\int \frac{1}{x\left(3x-5\right)}dx=\frac{2}{3}\int \frac{3}{5(3x-5)}-\frac{1}{5x}dx$

Using difference rule of integrals, we will get:

$\frac{2}{3}(\int \frac{3}{5(3x-5)}dx-\int \frac{1}{5x}dx)$

Now, we need to use u-substitution as:

Let $u=3x-5$ .

$\frac{du}{dx}=3$

$dx=\frac{1}{3}du$

$\int \frac{3}{5(3x-5)}dx= \frac{3}{5}\int \frac{1}{(u)}*\frac{1}{3}du=\frac{3}{5}*\frac{1}{3}\int \frac{1}{(u)}du=\frac{1}{5}ln|u|=\frac{1}{5}ln|3x-5|$

$\int \frac{1}{5x}dx=\frac{1}{5}\int \frac{1}{x}dx=\frac{1}{5}ln|x|$

Substitute back these values:

$\frac{2}{3}(\int \frac{3}{5(3x-5)}dx-\int \frac{1}{5x}dx)=\frac{2}{3}(\frac{1}{5}ln|3x-5|-\frac{1}{5}ln|x|)$

Let us add a constant C.

$\frac{2}{3}(\frac{1}{5}ln|3x-5|-\frac{1}{5}ln|x|)+C$

Therefore, our required integral would be $\frac{2}{3}(\frac{1}{5}ln|3x-5|-\frac{1}{5}ln|x|)+C$ .

5 0

3 years ago

In Geometry, We Think About Objects In A Physical Space. In This Context What Is Length? How Many Dimensions Is Length Measured

Hitman42 [59]

length is Measured in only one dimension

7 0

3 years ago

How can u answer this question in words by the shadow u can tell it is 9 dark outside PLZ help

valentinak56 [21]

Ok. So remember those questions you got in kindergarten example: 40 people were asked which was the nicest fruit in their opinion and here is a graph of what they thought was the nicest. So people use number bars as a way to organize problems. Does this make any sense? I will help in comments if it doesn't.

5 0

3 years ago