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Inga [223]
3 years ago
12

The default case is required in the switch selection statement.

Computers and Technology
1 answer:
babunello [35]3 years ago
5 0

Answer: False

Explanation:

 The given statement is false, as it is not compulsory that the default case is require in switch selection statement. If the default case are not properly specified in the statement then, there will be no execution occur in the switch selection statement.

It is sometimes good to have default case in switch selection statement, but it is not mandatory. The default case only executed when the correct case is present and none of the case matches in the given statement.

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Write a story, a tale, a biography or a diary.
antoniya [11.8K]
I will write a very short story, so I hope this helps a little

The processing of gold: A diary entry

April 5/2018

I am the worlds most precious metal. 
I am worth more than any silly diamond, and far more stronger than Iron. No one can come close to being as important as I.

I start as a tiny mineral, found underground where I spend my days perfecting myself. Most might find relatives of mine in water, buried among sand and dirt. Then we are put through the most rigorous of training until we are god.

Well, gold, but you know what I mean.

Once I am perfection, I will be sold among the masses of people.   I will be loved my all and crafted into everything. If I wanted, I could take over the world...a world of just gold, wouldn't that be magical?

Today I think I will be made into a ring, I hope I am not squeezed on some fat woman's finger.

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6 0
3 years ago
The internet has provided great opportunities for fundraising. true/false
alekssr [168]
True, sites such as kickstarter and just giving are fantastic examples of such.
8 0
3 years ago
(b) The CPU is responsible for processing instructions.
Yakvenalex [24]

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The CPU is responsible for processing instruction. CPU instruction processing goes through three stages. Fetch, Decode, and Execute.

When the program runs,  program code is copied from secondary storage into main memory. CPU's program counter set to the first instruction of the program stored in memory where the program starts executing.

When a program is being executed, it goes through fetch-decode-cycle. which repeats over and over again until reaching the STOP instruction.

The processor check which next instruction to be executed, then the processor fetches that instruction value from the memory location.  once the instruction being fetched it gets decoded and executed. This instruction processing cycle repeating until the CPU finds a stop instruction.

6 0
3 years ago
Read 2 more answers
Question is attached as image, please help :>
harkovskaia [24]

Answer:

Proved

Explanation:

Given

X = (a.\bar b)+(\bar a.b)

(a + b)\ .  \frac{}{a.b}

Required

Find out why they represent the same

To do this, we simplify either (a + b)\ .  \frac{}{a.b} or X = (a.\bar b)+(\bar a.b)

In this question, I will simplify (a + b)\ .  \frac{}{a.b}

Apply de morgan's law

(a + b)\ .  \frac{}{a.b} = (a + b) . (\bar a + \bar b)

Apply distribution property

(a + b)\ .  \frac{}{a.b} = a.\bar a + a.\bar b + \bar a . b + b . \bar b

To simplify, we apply the following rules:

a.\bar a = 0 --- Inverse law

b.\bar b = 0 --- Inverse law

So, the expression becomes

(a + b)\ .  \frac{}{a.b} = 0 + a.\bar b + \bar a.b + 0

(a + b)\ .  \frac{}{a.b}  = a.\bar b + \bar a.b

Rewrite as:

(a + b)\ .  \frac{}{a.b}  = (a.\bar b)+(\bar a.b)

From the given parameters:

X = (a.\bar b)+(\bar a.b)

This implies that:

(a + b)\ .  \frac{}{a.b} when simplified is X or (a.\bar b)+(\bar a.b)

3 0
3 years ago
What is the missing line?
Marta_Voda [28]

Answer: i think it is >>> myDeque.clear()

5 0
3 years ago
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