To solve this problem, we must assume ideal gas behaviour so
that we can use Graham’s law:
vA / vB = sqrt (MW_B / MW_A)
where,
<span>vA = speed of diffusion of A (HBR)</span>
vB = speed of diffusion of B (unknown)
MW_B = molecular weight of B (unkown)
MW_A = molar weight of HBr = 80.91 amu
We know from the given that:
vA / vB = 1 / 1.49
So,
1/1.49 = sqrt (MW_B / 80.91)
MW_B = 36.44 g/mol
Since this unknown is also hydrogen halide, therefore this
must be in the form of HX.
HX = 36.44 g/mol , therefore:
x = 35.44 g/mol
From the Periodic Table, Chlorine (Cl) has a molar mass of
35.44 g/mol. Therefore the hydrogen halide is:
HCl
What do the bubbles indicate? <span>chemical reaction with HCl, release of H2(g)
</span>
Where the substances are located in relation to one another on the periodic table and the activity series? <span>A is above B on the periodic table but B is above A in the activity series.
</span>
The name of the family the substances could be in ? <span>alkaline earth, alkali metals. Either group 1 or group 2.
</span>
<span>What substance will have a larger atomic radius? B</span>
What substance will have a larger ionization energy? A
Negative charge
(+1)+(0)+(-1)+(-1)= -1
Answer:
The difference between sulfate and sulfite is, Sulfate (SO4) has 1 atom of Sulphur and 4 atoms of Oxygen. sulfite (SO3) has 1 atom of sulfur and 3 atoms of Oxygen.
Explanation:
