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olya-2409 [2.1K]
3 years ago
15

In Rutherford experiment some alpha particles fired at a gold foil bounced backward as a result of ... A.reflection from the sur

faces of gold atoms B.electrostatic repulsion by gold nuclei C.electrostatic repulsion by electronsD.all of the aboveE.none of the above
Chemistry
2 answers:
IRINA_888 [86]3 years ago
6 0

Answer: The correct option is B (electrostatic repulsion by gold nuclei).

Explanation:

In the Rutherford's experiment, he used positively charged particles called alpha particles to bombard an atom in order to find out what is inside the atom. Together with two other scientists, Geiger and Marsden, they used a narrow beam of alpha particles emitted from a radioactive source to bombard a thin gold foil. The scattering of the particles from the gold foil was detected by a movable zinc sulphide screen which could be rotated to various positions around the foil.

Each time an alpha particle hit the screen, a visible flash of light or scintillation was produced. This was observed by a microscope attached to the screen. It was then observed that some of the particles followed a straight path through the gold foil while a few where scattered in a backward direction. This was as a result of electrostatic repulsion by gold nuclei which occurs due to the greater part of the mass of the atom was concentrated in a minute nucleus with positive charge.

Amanda [17]3 years ago
3 0

Answer:

B.electrostatic repulsion by gold nuclei

Explanation:

According to Rutherford's experiment, a thin gold foil was bombarded with alpha particles. Some of the particles passed through the foil undeviated, some were scattered through large angles while some bounced backwards.

It follows that the particles that bounced backwards must have encountered a massive particle of like charge.

The atom is composed of a nucleus which contains positively charged particles. Some of the alpha particles which are positively charged particles bounced back when they encountered the positively charged particles in the nucleus.

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vampirchik [111]

Explanation:

10 moles h20 is required

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Find the theoretical oxygen demand for the
never [62]

Answer:

a) 213.3 mg/L

b) 62.61 mg/L

c) 0.0225 mg/L

Explanation:

Theoretical oxygen demand (ThOD)is essentially the amount of oxygen required for the complete degradation of a given compound into the final oxidized products

a) Given:

Concentration of acetic acid,[CH3COOH] = 200 mg/L

CH3COOH + 2O2 \rightarrow 2CO2 + 2H2O

ThOD = \frac{mass\ O2}{mass\ CH3COOH} * conc. CH3COOH

Based on the reaction stoichiometry:

mass of CH3COOH = 60 g

mass of O2= 2(32) = 64 g

ThOD = \frac{64 g}{60 g} * 200mg/L = 213.3 mg/L

b) Given:

Concentration of ethanol, [C2H5OH] = 30 mg/L

C2H5OH + 3O2 \rightarrow 2CO2 + 3H2O

ThOD = \frac{mass\ O2}{mass\ C2H5OH} * conc. C2H5OH

Based on the reaction stoichiometry:

mass of C2H5OH = 46 g

mass of O2= 3(32) = 96 g

ThOD = \frac{96 g}{46 g} * 30mg/L = 62.61 mg/L

c) Given:

Concentration of sucrose, [C12H22O11] = 50 mg/L

C12H22O11 + 12O2 \rightarrow 12CO2 + 11H2O

ThOD = \frac{mass\ O2}{mass\ C22H22O11} * conc. C12H22O11

Based on the reaction stoichiometry:

mass of C12H22O11 = 342 g

mass of O2= 12(32) = 384 g

ThOD = \frac{384 g}{342 g} * 50mg/L = 0.0225 mg/L

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4 years ago
Need some help with this Chem Question :)
Kruka [31]

Answer:

Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂

Explanation:

The activity series helps us to easily define whether or not a reaction will occur.

Elements at the top of the activity series are highly reactive and will always displace those at the bottom of the series in any reaction.

With the above information in mind, let us answer the questions given above.

Ag + NaNO₃ —> Na + AgNO₃

The above reaction will not occur because Na is higher than Ag in the activity series. Thus, Ag cannot displace Na from solution.

Pb + Mg(NO₃)₂ —> Pb(NO₃)₂ + Mg

The above reaction will not occur because Mg is higher than Pb in the activity series. Thus, Pb cannot displace Mg from solution.

Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂

The above reaction will occur because Mg is higher than Fe in the activity series. Thus, Mg will displace Fe from solution.

Cu + Mg(NO₃)₂ —> Cu(NO₃)₂ + Mg

The above reaction will not occur because Mg is higher than Cu in the activity series. Thus, Cu cannot displace Mg from solution.

From the above illustration, only

Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂

Will occur.

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Answer:

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Explanation:

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Answer:

0.535 g

Explanation:

The reaction that takes place is:

  • NaCl + AgNO₃ → AgCl + NaNO₃

First we <u>calculate how many AgNO₃ moles are there in 25.0 mL of a 0.366 M solution</u>, using the <em>definition of molarity</em>:

  • Molarity = moles / liters
  • moles = Molarity * liters

<em>Converting 25.0 mL to L </em>⇒ 25.0 / 1000 = 0.025 L

  • moles = 0.366 M * 0.025 L = 0.00915 mol AgNO₃

Then we <u>convert AgNO₃ moles into NaCl moles</u>:

  • 0.00915 mol AgNO₃ * \frac{1molNaCl}{1molAgNO_3} = 0.00915 mol NaCl

Finally we<u> convert NaCl moles into grams</u>, using its <em>molar mass</em>:

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