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Alex73 [517]
3 years ago
11

Which equation has only once solution? |x-5|=-1 |-6-2x|=8 |5x+10|=10 |-6x+3|=0

Mathematics
2 answers:
Irina18 [472]3 years ago
7 0

Answer:

|x-5|=-1 has no solution because the | | makes everything positive and -1 is negative

|-6-2x|=8 has two solutions x = -7 and x= 1

|5x+10|=10 has two solutions x= 0 and x= -4

|-6x+3|=0 has one solution x=1/2

Step-by-step explanation:

|-6x+3|=0 is the answer hope this helps

Aleks04 [339]3 years ago
5 0

Answer:

The first equation has no solution, you cannot get a negative out of absolute value. The second has two solutions. <u>The third has only one solution, x is equal to 0.</u> The last has two solutions.

<u />

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Match the equation with its corresponding solution for x: 4x+7=35
Goryan [66]
4x+7=35
4x=28
x=7

A corresponding solution of the matching equation is a fancier way of telling you to find the number that represents x
7 0
4 years ago
In a standard normal distribution, about _________% of the scores fall above a z-score of 3.00
Katarina [22]

The normal rule to remember is 68-95-99.7, i.e. plus or minus three sigma corresponds to 99.7% of the probability. That leaves 0.3% in the two tails, or 0.15% in the tail above 3 sigma.

Answer: 0.15%


7 0
3 years ago
1. A farmer divided a field into 1-foot by 1-foot sections and tested soil samples from 32 randomly selected sections in the fie
Ad libitum [116K]
Part A

Answers:
Mean = 5.7
Standard Deviation = 0.046

-----------------------

The mean is given to us, which was 5.7, so there's no need to do any work there.

To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046

================================================

Part B

The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949

The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67

================================================

Part C

Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657

L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99

U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21
5 0
3 years ago
Scores on a dental anxiety scale range from 0​ (no anxiety) to 20​ (extreme anxiety). The scores are normally distributed with a
solniwko [45]

Answer:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Step-by-step explanation:

The following information is missing in the question:

We have to find z-score for the given score on this dental anxiety scale: 12, 6

We are given the following information in the question:

Mean, μ = 11

Standard Deviation, σ = 4

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

where x is the given score on this dental anxiety scale.

For x = 12

z_{score} = \displaystyle\frac{12-11}{4} = 0.25

For x = 6

z_{score} = \displaystyle\frac{6-11}{4} = -1.25

6 0
4 years ago
Please do the agree or disagree part and justification
Jlenok [28]

Answer:

<em>We disagree with Zach and Delia and agree with Alicia</em>

Step-by-step explanation:

The domain of a function is the set of values of the independent variable that the function can take according to given rules or restrictions.

The range is the set of values the dependent variable can take for every possible value of the domain.

The graph shows a continuous line representing the values of the function. We must take a careful look to the values of x (horizontal axis) where the function exists. It can be done by drawing an imaginary vertical line passing through the value of x. If that line touches the graph of the function, it belongs to the domain. It's clear that every value of x between -5 and 3 (both inclusive because there are solid dots in the extremes) belong to the domain:

Domain: -5\leq x \leq 3

The range is obtained in a similar way as the domain, but the imaginary lines must be horizontal. That gives us the values of y range from -7 to 5 both inclusive:

Range:

-7\leq y \leq 5

Thus we disagree with Zach and Delia and agree with Alicia

8 0
3 years ago
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