Question

What is the factored form of r^27-s^30

Answer 1

Answer:

$(r^9-s^{10})(r^{18}+r^9s^{10}+s^{20})$

Step-by-step explanation:

$r^{27}-s^{30}$

We know a^3 - b^3 formula

$a^3 - b^3 = (a-b)(a^2+ab+b^2)$

Rewrite r^27-s^30 in cube form

$(r^{9})^3-(s^{10})^3$

Now we apply the formula. we have r^9 in the place of 'a'

and s^10 in the place of 'b'

$(r^{9})^3-(s^{10})^3$

$(r^9-s^{10})((r^9)^2+r^9s^{10}+(s^{10})^2)$

$(r^9-s^{10})(r^{18}+r^9s^{10}+s^{20})$

Answer 2

(r^9 - s^10) (r^18 + r^9 s^10 + s^20) 
Hope this helps