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andre [41]
4 years ago
8

Need to find a fraction that is greater than 1/8 but less than 1/2.

Mathematics
2 answers:
o-na [289]4 years ago
8 0

Answer:

1/4

Step-by-step explanation:

Dahasolnce [82]4 years ago
7 0

Answer:

1/4

Step-by-step explanation:

with fractions, the smaller the donomonator, the greater the fraction and vise versa.

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Can someone plz help? I do not understand
Slav-nsk [51]

Answer:

y=x no

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y=3+x no

Step-by-step explanation:

4 0
4 years ago
Evaluate the integral by changing to polar coordinatesye^x dA, where R is in the first quadrant enclosed by the circle x^2+y^2=2
34kurt
\displaystyle\iint_Rye^x\,\mathrm dA=\int_{\theta=0}^{\theta=\pi/2}\int_{r=0}^{r=5}r^2\sin\theta e^{r\cos\theta}\,\mathrm dr\,\mathrm d\theta

which follows from the usual change of coordinates via

\begin{cases}\mathbf x(r,\theta)=r\cos\theta\\\mathbf y(r,\theta)=r\sin\theta\end{cases}

and Jacobian determinant

|\det J|=\left|\begin{vmatrix}\mathbf x_r&\mathbf x_\theta\\\mathbf y_r&\mathbf y_\theta\end{vmatrix}\right|=|r|

Swap the order, so that the integral is

\displaystyle\int_{r=0}^{r=5}\int_{\theta=0}^{\theta=\pi/2}r^2\sin\theta e^{r\cos\theta}\,\mathrm d\theta\,\mathrm dr

and now let \sigma=r\cos\theta, so that \mathrm d\sigma=-r\sin\theta. Now, you have

\displaystyle\int_{r=0}^{r=5}\int_{\sigma=0}^{\sigma=r}re^\sigma\,\mathrm d\sigma\,\mathrm dr=\int_{r=0}^{r=5}r(e^r-1)\,\mathrm dr=4e^5-\dfrac{23}2
7 0
3 years ago
Help me please I will give 5 stars a thanks a crown and 10 points
Umnica [9.8K]
Thats hard bro hopefully somebody helps you figure it out
6 0
3 years ago
Read 2 more answers
if the area of a circle is represented by A=21π, what is the radius of the circle? round your answer to the nearest tenth
Reptile [31]
The equation is actually
circle area = PI * radius^2
radius = square root (area / PI)


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40 POINTS !! 40 POINTS !!<br><br> PLEASE HELP , DONT SKIP !<br><br> NO LINKS OR FILES.
laiz [17]
UV=(-9–(-2)),(-3–(-6))
UV=(-9+2),(-3+6)
UV=(-7,3)
I think you find the change in the x and y components. I’m not really sure
5 0
3 years ago
Read 2 more answers
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