4 years ago

Need to find a fraction that is greater than 1/8 but less than 1/2.

Mathematics

2 answers:

o-na [289]4 years ago

8 0

Answer:

1/4

Step-by-step explanation:

Dahasolnce [82]4 years ago

7 0

Answer:

1/4

Step-by-step explanation:

with fractions, the smaller the donomonator, the greater the fraction and vise versa.

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Can someone plz help? I do not understand

Slav-nsk [51]

Answer:

y=x no

y=12x yes

y=1.6x yes

y=3/(4x) no

y=2x+1 no

y=3+x no

Step-by-step explanation:

4 0

4 years ago

Evaluate the integral by changing to polar coordinatesye^x dA, where R is in the first quadrant enclosed by the circle x^2+y^2=2

34kurt

$\displaystyle\iint_Rye^x\,\mathrm dA=\int_{\theta=0}^{\theta=\pi/2}\int_{r=0}^{r=5}r^2\sin\theta e^{r\cos\theta}\,\mathrm dr\,\mathrm d\theta$

which follows from the usual change of coordinates via

$\begin{cases}\mathbf x(r,\theta)=r\cos\theta\\\mathbf y(r,\theta)=r\sin\theta\end{cases}$

and Jacobian determinant

$|\det J|=\left|\begin{vmatrix}\mathbf x_r&\mathbf x_\theta\\\mathbf y_r&\mathbf y_\theta\end{vmatrix}\right|=|r|$

Swap the order, so that the integral is

$\displaystyle\int_{r=0}^{r=5}\int_{\theta=0}^{\theta=\pi/2}r^2\sin\theta e^{r\cos\theta}\,\mathrm d\theta\,\mathrm dr$

and now let $\sigma=r\cos\theta$ , so that $\mathrm d\sigma=-r\sin\theta$ . Now, you have

$\displaystyle\int_{r=0}^{r=5}\int_{\sigma=0}^{\sigma=r}re^\sigma\,\mathrm d\sigma\,\mathrm dr=\int_{r=0}^{r=5}r(e^r-1)\,\mathrm dr=4e^5-\dfrac{23}2$

7 0

3 years ago

Help me please I will give 5 stars a thanks a crown and 10 points

Umnica [9.8K]

Thats hard bro hopefully somebody helps you figure it out

6 0

3 years ago

Read 2 more answers

if the area of a circle is represented by A=21π, what is the radius of the circle? round your answer to the nearest tenth

Reptile [31]

The equation is actually
circle area = PI * radius^2
radius = square root (area / PI)

5 0