Answer:
H0: p(1980) = p(2010) ; H1 : P(1980) > P(2010)
0.02
Step-by-step explanation:
Given that:
Sample size in both 1980 and 2010 = 1000 samples :
Proportion in favor :
P(1980) = 0.66
P(2010) = 0.64
To test the hypothesis :
Null hypothesis :
Proportion in favor are the same in both years
Null hypothesis = H0 = p(1980) = p(2010)
Alternative hypothesis :
Proportion in favor in 1980 is greater than that in 2010
Alternative hypothesis = H1 : P(1980) > P(2010)
The sample statistic :
P(1980) - p(2010)
0.66 - 0.64
= 0.02
Answer:
where is the expression
Step-by-step explanation:
（＾_＾）（＾_＾）（＾_＾）
Answer:
8500 ft²
Step-by-step explanation:
First we need to find the area of the non shaded region within this shaded region. To find the area of this non shaded rectangle, use the formula base×height.
20×100=2000 ft².
Now we need to find the height and width of the shaded region which is,
25+25+20=70 Height
25+25+100=150 Width
mutiply these numbers 150×70=10500 ft²
Now we just need to subtract that inside area.
10500-2000=8500 ft²
I think it is 8,4 let me now if it is right
