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snow_lady [41]
3 years ago
7

On a numberline, X is positioned at -9. What is the absolute value of X?

Mathematics
1 answer:
Molodets [167]3 years ago
8 0
The absolute value is 9
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Find the inequality represented by the graph
bezimeni [28]
The answer is y ≥ 1/2x
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2 years ago
Read 2 more answers
Please help!!!!
tatyana61 [14]

Answer:

Step-by-step explanation:

From the figure attached,

If the figures shown are congruent (Equal in shape and size), length of all the sides must be equal.

Therefore, sides sides CD and GH must be equal in measures.

Distance between the two points (x_1,y_1) and (x_2,y_2) is given by,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Length of the side CD having ends C(-4, 4) and D(0, 5) will be,

CD = \sqrt{(-4-0)^2+(4-5)^2}

CD = \sqrt{(16+1)}

     = \sqrt{17}

Length of GH having ends G(0, -4) and H(4, -5) will be,

GH = \sqrt{(0-4)^2+(-4+5)^2}

      = \sqrt{16+1}

      = \sqrt{17}

Therefore, m(CD) = m(GH)

Similarly, we can prove all corresponding sides of two figures equal in measure.

This shows ABCD ≅ EFGH.

3 0
3 years ago
In a college biology class, only half of the class earned a passing grade, Out of all the students
Oduvanchick [21]

Answer:

b 30% is the right answer

6 0
3 years ago
What are the trigonometric ratios of in a right triangle with the given value tan A = 9/40
hjlf

The trigonometric ratios of the right triangle with the given value tan A = 9 / 40 are

sin A = 9 / 41

cos A = 40 / 41

<h3>Trigonometric ratios</h3>

Trigonometric ratios are used to solve for the sides and angles of a right angle triangle.

Therefore,

sin A = opposite / hypotenuse

cos A = adjacent / hypotenuse

tan A = opposite / adjacent

Using Pythagoras theorem, let find the hypotenuse side

c² = 40² + 9²

c = √1681

c = 41

Therefore,

sin A = 9 / 41

cos A = 40 / 41

learn more on trigonometric ratios here: brainly.com/question/24320387

#SPJ1

8 0
1 year ago
Solve the qn in attachment .​
galina1969 [7]

Answer:

\implies \dfrac{ -4x+7}{2(x-2) }

Step-by-step explanation:

The given expression to us is ,

\implies \dfrac{\frac{ 3}{x-1} -4 }{ 2 -\frac{2}{x-1}}

Now take the LCM as ( x - 1 ) and Simplify , we have ,

\implies \dfrac{\frac{ 3 -4(x-1) }{x-1} }{ \frac{2-2(2x-1)}{x-1}}

Simplifying further , we get ,

\implies \dfrac{ -4x+7}{2(x-2) }

<u>Hence the second option is correct.</u>

5 0
2 years ago
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