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Afina-wow [57]
3 years ago
9

The average of A and B is 6. The average of X, Y, and Z is 16. What is the average of A, B, X, Y, and Z?

Mathematics
1 answer:
ser-zykov [4K]3 years ago
4 0

Answer:

12

Step-by-step explanation:

Average of A and B is 6

(A+B) /2 = 6

Multiply each side by 2

A+B = 12

average of X, Y, and Z is 16

(X+Y+Z)/3 = 16

Multiply each side by 3

(X+Y+Z) = 48

To find the average of all of them

(A+B+X+Y+Z)/5

replace A+B with 12 and X+Y+Z with 48

(12+48)/5

60/5 = 12

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Yuri [45]

Answer:

34 feet

Step-by-step explanation:

From the question, we are told that:

If the room is 30 feet high at the center and 90 feet wide at the floor,

Entire width of the room = 90 feet = 2a

a = 90/2 = 45

Height of the room = b = 30 feet

Foci (c)² = a² - b²

c = √a² - b²

c = √45² - 30²

c = √1125

c = 33.541019662 feet

Approximately to the nearest whole number = 34 feet

Denise and Donna should each stand 34 ft from the outer wall so that they will be positioned at the foci of the ellipse

7 0
3 years ago
NEED HELP!!!!!!!!!!!!!!!!! Math problem! Please help!
Elanso [62]

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8 0
3 years ago
Use the given information to solve for x and y
Anuta_ua [19.1K]

Answer:

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Step-by-step explanation:

Equalateral triangle means all sides are equal.

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4 0
3 years ago
4 1/2 cups of salad dressing fill 3 3/4 identical jars. How many cups fill each jar
matrenka [14]

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Step-by-step explanation:

5 0
2 years ago
X+y+z=12<br> 6x-2y+z=16<br> 3x+4y+2z=28<br> What does x, y, and z equal?
lianna [129]

Answer:

x = 20/13 , y = 16/13 , z = 120/13

Step-by-step explanation:

Solve the following system:

{x + y + z = 12 | (equation 1)

6 x - 2 y + z = 16 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Swap equation 1 with equation 2:

{6 x - 2 y + z = 16 | (equation 1)

x + y + z = 12 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Subtract 1/6 × (equation 1) from equation 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+(4 y)/3 + (5 z)/6 = 28/3 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Multiply equation 2 by 6:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Subtract 1/2 × (equation 1) from equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

0 x+5 y + (3 z)/2 = 20 | (equation 3)

Multiply equation 3 by 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

0 x+10 y + 3 z = 40 | (equation 3)

Swap equation 2 with equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+8 y + 5 z = 56 | (equation 3)

Subtract 4/5 × (equation 2) from equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+(13 z)/5 = 24 | (equation 3)

Multiply equation 3 by 5:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+13 z = 120 | (equation 3)

Divide equation 3 by 13:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Subtract 3 × (equation 3) from equation 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y+0 z = 160/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Divide equation 2 by 10:

{6 x - 2 y + z = 16 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Add 2 × (equation 2) to equation 1:

{6 x + 0 y+z = 240/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Subtract equation 3 from equation 1:

{6 x+0 y+0 z = 120/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Divide equation 1 by 6:

{x+0 y+0 z = 20/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Collect results:

Answer:  {x = 20/13 , y = 16/13 , z = 120/13

8 0
3 years ago
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