Question

V= 512^2/3* 19683^1/3*256^1/4

Answer 1

Answer:

V=512^2/3* 19683^1/3*256^1/4    = 6912

Step-by-step explanation:

V= $(512^{\frac{2}{3} } ) \times (19683^{\frac{1}{3} } )\times (256^{\frac{1}{4} } )$

As

$2^{9} = 512\\2^{8} = 256\\19683^{\frac{1}{3} } = 27$

putting values in equation

V= $2^{9(^{\frac{2}{3} } )} \times 27 \times 2^{8^({\frac{1}{4}) } }$  let it be equation 1

As

$2^9^{\frac{2}{3} } = 2^6 according\,to\,exponential\,rule\\2^8^\frac{1}{4} = 2^2 according\,to\,exponential\,rule$

putting values in equation 1

$V= 2^6\times 27\times 2^2$

According to exponential rule $2^6 \times 2^2 = 2^8$

V=$2^8 \times 27$

$V=256\times 27\\V=6912$

So

V= 6912

Keywords: Algebra

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