Answer:
mean = 1 power failure
variance = 1 (power failure)²
Step-by-step explanation:
Since the mean is computed as
mean = E(x) = ∑ x * p(x) for all x
then for the random variable x=power failures , we have
mean = ∑ x * p(x) = 0 * 0.4 + 1* 0.3 + 2*0.2 + 3* 0.1 = 1 power failure
since the variance can be calculated through
variance = ∑[x-E(x)]² * p(x) for all x
but easily in this way
variance = E(x²) - [E(x)]² , then
E(x²) = ∑ x² * p(x) = 0² * 0.4 + 1²* 0.3 + 2²*0.2 + 3²* 0.1 = 2 power failure²
then
variance = 2 power failure² - (1 power failure)² = 1 power failure²
therefore
mean = 1 power failure
variance = 1 power failure²
Answer:
B. 
+ 2x³ - 8x² - 22x - 15
Step-by-step explanation:
1. (3x² - 2x - 3)(5x² + 4x +5)
+ 12x³ + 15x² - 10x³ - 8x² - 10x - 15x² - 12x - 15
2. Combine like terms
+ 2x³ - 8x² - 22x - 15
Answer: y + x = ?
y - x = ?
y times x = ?
y / x = ?
Step-by-step explanation: If 1 is correct tell me, if none are, i will edit :D
Answer:
1.26kg per package
Step-by-step explanation:
30.28/24= 1.2616...
