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klio [65]
3 years ago
14

There is $2,134 in a savings account. If next year the money is two times as much, what is the total amount in the savings accou

nt?
Mathematics
2 answers:
Softa [21]3 years ago
7 0

You'll duplicate the money in the account, so, 2,134 . 2 = $4,268

Dafna1 [17]3 years ago
6 0

Hello!

To find our answer, we just multiply by 2.

2,134(2)=4,268

Therefore, there would be $4,268.

I hope this helps!

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Solve for x<br><br> 0.2x -1.1<br> _______ =0.5<br> 5
lora16 [44]

I did it i took a picture

Hope its ok


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2 years ago
A light bulb consumes 960 watt-hours per day. How many watt-hours does it consume in
Kobotan [32]
960 watt-hpd 

5 x 60/6 = 50

50 x 960 = 48,000

Answer is: -->> 48,000



5 0
2 years ago
Simplify the product 7x (x + 4)
lora16 [44]

7x+4 is the correct awnser(i think)

3 0
3 years ago
Read 2 more answers
true or false: the points (6, 13), and (21, 33) and (99, 137) all lie on the same line. th equation of the lines is y + /3x + 5.
Phoenix [80]

Answer:

point A (6,13) lies on the equation.  True

given point  B(21,33) lies on the equation.  True

given point  C (99, 137) lies on the equation.  True

The equation that was given was  y = 4/3x + 5

Now,check the given equation for the given points.

1)  A (6,13)

Substitute x = 6 in the given equation y = 4/3x +5

y = 4/3(6) + 5 = 4(2) + 5 = 8+5 = 13

y=13

the given point A (6,13) lies on the equation.

2)  B  (21,33)

Substitute x = 21 in the given equation y=4/3x+5

y=4/3(21) + 5 = 4(7) + 5=28+5=33

y = 33

the given point  B(21,33) lies on the equation.

3)  C (99, 137)

Substitute x = 99 in the given equation y = 4/3x + 5

y=4/3(99) + 5 = 4(33) + 5 = 132 + 5 = 137

y = 137

the given point  C (99, 137) lies on the equation.

There is your answer

8 0
2 years ago
Determine if the function is linear or nonlinear . EXPLAIN​
nordsb [41]

Answer:

it is not linear

Step-by-step explanation:

Linear function means that same increments in x yield uniform increments in y.

First 2 lines: x grows from -5 to 0, so increment in x is 5. For said interval, y grows from 3 to 7, so increment in y is 4.

Then, x grows from 0 to 5, so increment in x is again 5. Now, for the same increase of x, y grows from 7 to 10, so increment now in y is 3.

In the first "5" interval of x, y grew 4, and in the second "5" interval of x y grew 3 ⇒ it is not linear.

The function would have been linear, if last y value had been 11.

5 0
2 years ago
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