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sergeinik [125]
3 years ago
12

What does 0 represent?

Mathematics
1 answer:
postnew [5]3 years ago
7 0

Answer:

lol more context please

Step-by-step explanation:

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Darnell is trying to decide on the dimensions of his next painting. He wants to length to vary inversely with the width. The tab
alexandr1967 [171]

<em>Answer:</em>

<em>D)</em>

<em>Step-by-step explanation:</em>

<em>We know that it cannot be C since z is not involved in this problem.</em>

<em>a) 3/20x</em>

<em>Try with 20 = x</em>

<em>3/440 ≠ 3</em>

<em>A is not the answer.</em>

<em>b) 60x</em>

<em>Try with 20 = x</em>

<em>1800 ≠ 3</em>

<em>B is not the answer.</em>

<em>c) 60/x</em>

<em>Try with 20 = x</em>

<em>3 = 3</em>

<em>Try with 15 = x</em>

<em>4 = 4</em>

<em>D is your answer.</em>

<em>Hope this helps. Have a nice day. Oh, and one more thing. Surprised to see I'm not stealing points?</em>

8 0
2 years ago
PLEASE HELP ASAP!! <br> Please its due in 5 min!
-Dominant- [34]
Answer:

first question) m = - 63
second question) y = 4

sorry if this is late, hope this helped!
5 0
2 years ago
What is the quotient of 30 and 3? A 33 B 27 C 90 D 10
Komok [63]
I am just guessing but you might try A
7 0
2 years ago
Can someone please let me know if this is correct or not??
AURORKA [14]
Yes your answer is correct
3 0
3 years ago
Anybody know the answer?
makvit [3.9K]

The first thing we need to do is take in all this information. We already know that the answer is between 0 and 7 because Line Segment AC is equal to 7. Second of all, it is recommended to solve this problem on paper to make it easier. You write the measurement under each individual Line Segment. Now we have to try to find a way how to subtract the Line Segments in order to get the measurement of Line Segment BC. If we were to write an equation. We would get mAB + mBC + mCD + mDE = mAE . We now try to think about the values that they give us to try to simplify it as much as possible. That's all that I can give you. I am sorry. This is a pretty tough and evil question.

5 0
3 years ago
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