First you have to rewrite the equation:
(x ÷ 4) + 8 = 38
Second you have to write the division as fraction:
(¼x) + 8 = 38
Third you have to take off the unecessary bracket:
¼x + 8 = 38
Fourth multiply 8 and 38 by 4
x + 32 = 152
Fifth step move the constant to the right hand and change the sign.
x = 152 - 32
Then subtract:
x = 120
Hope this helps :))
Answer:
Step-by-step explanation:
given a point
the equation of a line with slope m that passes through the given point is
or equivalently
.
Recall that a line of the form
, the y intercept is b and the x intercept is
.
So, in our case, the y intercept is
and the x intercept is
.
In our case, we know that the line is tangent to the graph of 1/x. So consider a point over the graph
. Which means that 
The slope of the tangent line is given by the derivative of the function evaluated at
. Using the properties of derivatives, we get
. So evaluated at
we get 
Replacing the values in our previous findings we get that the y intercept is

The x intercept is

The triangle in consideration has height
and base
. So the area is

So regardless of the point we take on the graph, the area of the triangle is always 2.
Answer:
Yes
Step-by-step explanation:
ΔMNL ≅ ΔQNL by ASA or AAS
by ASA
Proof:
∠ LNM = ∠LNQ =90
LN = LN {Common}
∠MLN = ∠QLN {LN bisects ∠ L}
By AAS
∠Q + ∠QLN + ∠LNQ = 180 {Angle sum property of triangle}
∠Q + 32 + 90 = 180
∠Q + 122 = 180
∠Q = 180 -122 =
∠Q = 58
∠Q = ∠M
∠MNL =∠QNL = 90
LN = LN {common side}
I think it’s going to be 7! Because since the other triangle is 1 and 3 it’s just 2 more so I just added to more to 5 getting me 7!! I think lol