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3 years ago

Which of these statements is true about adaptive evolution?

Mathematics

1 answer:

AveGali [126]3 years ago

3 0

Answer:

Adaptive evolution is always changing because the environment is changing continuously.

Hence,

The right answer would be :

Adaptive evolution is a fluctuating change in a trait

Step-by-step explanation:

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Draw and label the final image of △ABC after the given sequence of transformations. Reflect △ABC over the y−axis and then transl

arlik [135]

Answer: The correct option is A.

Explanation:

From the given figure it is noticed that each box in the graph represents the length of 2 units. The coordinates of point A,B and C are (-1,1),(-3,3) and (-2,4) respectively.

If a point reflects over the y-axis then,

$(x,y)\rightarrow(-x,y)$

So after reflecting coordinates of point C become,

$(-2,4)\rightarrow(2,4)$

If a point translated by (a,b), then

$(x,y)\rightarrow(x+a,y+b)$

So, after reflection over y-axis followed by translation by (2,-2), the coordinate of C are,

$(2,4)\rightarrow(2+2,4-2)\\(2,4)\rightarrow(4,2)$

Similarly the image of point A and B are (3,-1) and (5,1) respectively.

The image of C after reflection over y-axis followed by translation by (2,-2) is (4,2), which is shown in only graph A, Therefore A is the correct option.

8 0

3 years ago

Help please this is expressions and equations!!

Yanka [14]

Answer:

Step-by-step explanation:

8 0

3 years ago

Va rog va rog va rog ajutatima !!!!!!!!!!!!!!PLS 3x-16<38

matrenka [14]

X will be less than 18 or X<18

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4 years ago

Find the total volume. Please show your work.

elena-s [515]

Answer:

Step-by-step explanation:

You have a half sphere and a cylinder.

Trick question! Note that the diameter of the cylinder is in meters, while the height is given in centimeters.

For cylinder:

radius r = 5 m

height h = 6 cm = 0.06 m

volume = πr²h = π(5²)(0.06) = 1.5π m³

For sphere:

radius r = 5 m

volume of sphere = (4/3)πr³

volume of half sphere = (2/3)πr³ = (2/3)π5³ = (250/3)π m³

Total volume = 1.5π + 250π/3 ≅ 266.5 m³

4 0

3 years ago

Solve this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7

ratelena [41]

Answer:

Solving this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7 we get x=2 and y=-3

Solution set = {2,-3}

Step-by-step explanation:

We need to solve this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7

let:

$3x-2y=12--eq(1)\\x+3y=-7 --eq(2)$

Finding value of x from equation 2 and putting in eq(1)

$From \ eq(2)\\x+3y=-7\\x=-7-3y$

Putting value of x in eq(1)

$3x-2y=12\\Put \ x=-7-3y\\3(-7-3y)-2y=12\\Solving\\-21-9y-2y=12\\-11y=12+21\\-11y=33\\y=\frac{33}{-11}\\y=-3$

So, we get y=-3

Now put value of y in equation 2 to find value of x

$x+3y=-7\\x+3(-3)=-7\\x-9=-7\\x=-7+9\\x=2$

So, we get value of x =2

So, solving this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7 we get x=2 and y=-3

Solution set = {2,-3}

4 0

3 years ago