Parameterize the lateral face
of the cylinder by
where
and
, and parameterize the disks
as
where
and
.
The integral along the surface of the cylinder (with outward/positive orientation) is then
When completing the square <span>x=9.12311 and </span><span>x=<span>0.876894</span></span>
Answer:
$1.75
Step-by-step explanation:
The selling for each candy bar may be determined by a set of linear equations. This pair of linear equations may be solved simultaneously by using the elimination method. This will involve ensuring that the coefficient of one of the unknown variables is the same in both equations.
It may be solved by substitution in that one of the variable is made the subject of the equation and the result is substituted into the second equation
.
Let the cost of a snack bag be s and that of a candy bar be c, then if on Wednesday the students or 23 snack bags and 36 candy bars that raised $114.75 on Thursday the seventh so 37 snack bags and 36 candy bars that raised $146.25
23s + 36c = 114.75
37s + 36c = 146.25
14s = 31.5
s = $2.25
23(2.25) + 36c = 114.75
36c = 114.75 - 51.75
36c = 63
c = 63/36
= $1.75
The density of an object is what i can’t see the question
Answer:
x = 7
y = 11
Step-by-step explanation:
Given the system;
y = 2x - 3
x + y = 18
1. Approach
The easiest way to solve this system of equations is to solve the second equation for the variable (y). Then add the systems, use algebra to solve for the value of (x), then substitute that value back into one of the original equations to solve for the value of (y). Another name for the method in use is the method of elimination, this is when a [erspm manipulates one of the equations in a system of the equation such that when they add the equations, one of the variables eliminatates. Thus, they can solve for the other variable and the backsolve for the value of the unknown variable.
2. Solve one of the equations for a variable
Manipulate the system such that each equation is solved for the same variable,
x + y = 18
Inverse operations,
x + y = 18
-18 -18
x + y - 18 = 0
-y -y
x - 18 = -y
3. Use elimination
Now substitute this back into the original system,
y = 2x - 3
-y = x - 18
Add the systems,
y = 2x - 3
-y = x - 18
_________
0 = 3x - 21
Inverse operations,
0 = 3x - 21
+21 +21
21 = 3x
/3 /3
7 = x
4. Find the value of the unknown variable
Backsovle to find the value of (y),
x + y = 18
Substitute,
7 + y = 18
Inverse operations,
7 + y = 18
-7 -7
y = 11
