The length of the rectangle is 20 inches, and the width of the rectangle is 4 inches if the table runner has an area of 80 square inches. The length and width of the table runner are whole numbers. The length is 5 times greater than the width.
<h3>What is the area of the rectangle?</h3>
It is defined as the space occupied by the rectangle which is planner 2-dimensional geometry.
The formula for finding the area of a rectangle is given by:
Area of rectangle = length × width
The area of the table runner = 80 square inches
Let's assume the length of the rectangle is L and the width is W
Then L = 5×W ...(1)
L×W = 80 ...(2)
Put the value of L in the equation (2)
5W(W) = 80
5W² = 80
W² = 16
W = ±4
Width cannot be negative.
W = 4 inches putting this value in the equation (1)
L = 5(4) = 20 inches
Thus, the length of the rectangle is 20 inches, and the width of the rectangle is 4 inches if the table runner has an area of 80 square inches. The length and width of the table runner are whole numbers. The length is 5 times greater than the width.
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Well to find this answer, I assume that you want me to help with finding the area. Let's start with the area of the stage. Off of the info you gave me, I assume that the stage and pit are rectangles. So to find the area of the rectangles, we need to use the area formula A=l×w. Plug in the numbers into the formula and we get A=10×5. So the area of the stage is 50 yards. Now do the same thing for the pit, and we get A=4×2. So the pit's area is 8 yards. Add 50 and 8 to get the total area and we get 58. So the stage and the orchestra pit take up 58 yards of floor space. Hope I helped!
The answer is 367,500 yards