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san4es73 [151]
2 years ago
13

Write the point-slope form with two points ..of the given line that passes through the points (0, -3) and (4, 1). Identify (x1,

y1) as (0, -3). Include your work in your final answer. Please SHOW ALL WORK.
Mathematics
1 answer:
frez [133]2 years ago
3 0
You need to find the slope too.
m  =  \frac{y2 - y1}{x2 - x1}  =  \frac{ - 3 - 1}{0 - 4}  =   \frac{ - 4}{ - 4}  =  \frac{1}{1}
point slope formula y - y1 = m(x - x1)
use (0, -3)
y - (-3) = 1 (x -0)
y + 3 = 1x
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The function f(x)=2x+1 is defined over the interval [2, 5]. If the interval is divided into n equal parts, what is the value of
vodomira [7]

Answer:

  D.  5 +6k/n

Step-by-step explanation:

The width of the interval is (5 -2) = 3. The width of one of n parts of it will be ...

  3/n

Then the difference between the left end point of the interval and the value of  x at the right end of the k-th rectangle will be ...

  k·(3/n) = 3k/n

So, the value of x at that point is that difference added to the interval's left end:

  2 + 3k/n

The value of the function for this value of x is ...

  f(2 +3k/n) = 2(2 +3k/n) +1 = (4 +6k/n) +1

  = 5 +6k/n

4 0
3 years ago
What is the factorization of 121b^4-49
Nezavi [6.7K]

121^4-49

(11^2+7)(11^2-7) 1. 121. 49

11. × 11. 7 × 7

4 0
3 years ago
The market and Stock J have the following probability distributions:
denis-greek [22]

Answer:

1) E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

2) E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

3) E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

4) E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

Step-by-step explanation:

For this case we have the following distributions given:

Probability  M   J

0.3           14%  22%

0.4           10%    4%

0.3           19%    12%

Part 1

The expected value is given by this formula:

E(X)=\sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

Part 2

E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

Part 3

We can calculate the second moment first with the following formula:

E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

Part 4

We can calculate the second moment first with the following formula:

E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

8 0
3 years ago
The midpoint of KL is M (-8,1). One endpoint is K (-6,5) find the coordinates of the other endpoint L
PSYCHO15rus [73]

Answer:

Midpoint (x , y) of two points is

( x1 + y1/2 , x2 + y2/2)

Midpoint of KL is M ( -8 , 1)

Let the coordinates of L be ( a , b)

From the above definition

Midpoint between K(-6 , 5) and

L ( a ,b) is

(-8 , 1) = ( -6+a/2 , 5+b/2)

Comparing first point with - 8

- 8 = -6 + a /2

Multiply through by 2

We get

-16 = - 6 + a

a = -16+6

a = - 10

Comparing the second point with 1

1 = 5+b/2

Multiply through by 2

2 = 5 + b

b = 2 - 5

b = -3

Therefore a = -10 and b = - 3

Hence the coordinates of

L is ( -10 , - 3)

Hope this helps

3 0
3 years ago
I need help. I suck at Geometry
Temka [501]

Answer:

25

Step-by-step explanation:

We can use the Pythagorean theorem to fin x

a^2 + b^2 = c^2  where a and b are the legs and c is the hypotenuse

7^2 + 24^2 = x^2

49+ 576 = x^2

625 = x^2

Take the square root of each side

sqrt( 625) = sqrt(x^2)

25 = x

4 0
3 years ago
Read 2 more answers
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