Answer:
D. 5 +6k/n
Step-by-step explanation:
The width of the interval is (5 -2) = 3. The width of one of n parts of it will be ...
3/n
Then the difference between the left end point of the interval and the value of x at the right end of the k-th rectangle will be ...
k·(3/n) = 3k/n
So, the value of x at that point is that difference added to the interval's left end:
2 + 3k/n
The value of the function for this value of x is ...
f(2 +3k/n) = 2(2 +3k/n) +1 = (4 +6k/n) +1
= 5 +6k/n
121^4-49
(11^2+7)(11^2-7) 1. 121. 49
11. × 11. 7 × 7
Answer:
1) 
2) 
3) 
And the variance would be given by:
![Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89](https://tex.z-dn.net/?f=Var%20%28M%29%3D%20E%28M%5E2%29%20-%5BE%28M%29%5D%5E2%20%3D%20207.1%20-%2813.9%5E2%29%3D%2013.89)
And the deviation would be:
4) 
And the variance would be given by:
![Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56](https://tex.z-dn.net/?f=Var%20%28J%29%3D%20E%28J%5E2%29%20-%5BE%28J%29%5D%5E2%20%3D%20194.8%20-%2811.8%5E2%29%3D%2055.56)
And the deviation would be:
Step-by-step explanation:
For this case we have the following distributions given:
Probability M J
0.3 14% 22%
0.4 10% 4%
0.3 19% 12%
Part 1
The expected value is given by this formula:

And replacing we got:

Part 2

Part 3
We can calculate the second moment first with the following formula:

And the variance would be given by:
![Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89](https://tex.z-dn.net/?f=Var%20%28M%29%3D%20E%28M%5E2%29%20-%5BE%28M%29%5D%5E2%20%3D%20207.1%20-%2813.9%5E2%29%3D%2013.89)
And the deviation would be:
Part 4
We can calculate the second moment first with the following formula:

And the variance would be given by:
![Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56](https://tex.z-dn.net/?f=Var%20%28J%29%3D%20E%28J%5E2%29%20-%5BE%28J%29%5D%5E2%20%3D%20194.8%20-%2811.8%5E2%29%3D%2055.56)
And the deviation would be:
Answer:
Midpoint (x , y) of two points is
( x1 + y1/2 , x2 + y2/2)
Midpoint of KL is M ( -8 , 1)
Let the coordinates of L be ( a , b)
From the above definition
Midpoint between K(-6 , 5) and
L ( a ,b) is
(-8 , 1) = ( -6+a/2 , 5+b/2)
Comparing first point with - 8
- 8 = -6 + a /2
Multiply through by 2
We get
-16 = - 6 + a
a = -16+6
a = - 10
Comparing the second point with 1
1 = 5+b/2
Multiply through by 2
2 = 5 + b
b = 2 - 5
b = -3
Therefore a = -10 and b = - 3
Hence the coordinates of
L is ( -10 , - 3)
Hope this helps
Answer:
25
Step-by-step explanation:
We can use the Pythagorean theorem to fin x
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
7^2 + 24^2 = x^2
49+ 576 = x^2
625 = x^2
Take the square root of each side
sqrt( 625) = sqrt(x^2)
25 = x