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faltersainse [42]
3 years ago
11

You have been hired as an efficiency expert for Math Nerds Inc. The company wants to cut costs and increase profits by increasin

g the number of math problems their employees can solve in a day. Your job is to help the Math Nerds employees solve math problems more quickly. Show the Math Nerds employees how to rework each problem below using a polynomial identity. (x2+y2)2=(x2-y2)2+(2xy)2
Show the Math Nerds employees how much time you save on each problem by using the polynomial identity to simplify.
1) ( x+2 ) 2 (x+2) 2 = (x+y) 2 =x 2 +2xy+ y 2
2) ( x−3 ) 3 (x−3) 3 = (x−y) 3 =x 3 −3 x 2 y+3x y 2 − y 3
Mathematics
1 answer:
dusya [7]3 years ago
4 0
So in order to find
(x+2)2
without writing (x+2)(x+2)=x2+2x+2x+4=x2+4x+4 instead say y=2 and use the identity to get
x2+2×2x+2^2=x2+4x+4
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Bruce Lovegren was born on September 27, 1950. On April 14, 1977, he purchased a $15,000 10-year term life insurance policy. Wha
telo118 [61]
Well it would be 10,000 dollars
3 0
4 years ago
) f) 1 + cot²a = cosec²a​
notsponge [240]

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).

\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}

csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.

\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}

Another identity is:

\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}

Therefore:

\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}

Another identity:

\displaystyle \large{\sin^2x+\cos^2x=1}

Therefore:

\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}\longrightarrow \boxed{ \frac{1}{\sin^2x}={\frac{1}{\sin^2x}}}

Hence proved, this is proof by using identity helping to find the specific identity.

6 0
3 years ago
A triangle has coordinates A(-3,5), B(-3,8)
ddd [48]

Answer:

A(-9,15); B(-9,24); C(6,15)

Step-by-step explanation:

multiply each number in the coordinates by 3

5 0
3 years ago
3x = y and x - 2y = 10​
Svetlanka [38]

Answer: Rewrite equations:

3x=y;x−2y=10

Step: Solve3x=yfor y:

3x=y

3x+−y=y+−y(Add -y to both sides)

3x−y=0

3x−y+−3x=0+−3x(Add -3x to both sides)

−y=−3x

−y

−1

=

−3x

−1

(Divide both sides by -1)

y=3x

Step: Substitute3xforyinx−2y=10:

x−2y=10

x−23x=10

−5x=10(Simplify both sides of the equation)

−5x

−5

=

10

−5

(Divide both sides by -5)

x=−2

Step: Substitute−2forxiny=3x:

y=3x

y=(3)(−2)

y=−6(Simplify both sides of the equation)

Step-by-step explanation:

6 0
3 years ago
The price of pakets of tea ir same as the price of 4 paket.How many packets of tea ate required to exchange 20 packets of coffee
Veronika [31]

Answer:

The answer I got was 16 if your using addition, but 5 if using multiplication

Step-by-step explanation:

5 0
3 years ago
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