The answer is 28 years
At = A0 * e^(-k * t)
At = 12 g
A0 = 15 g
k = 7.9 × 10^-3 = 0.0079
t = ?
12 = 15 * e^(-0.0079 * t)
12/15 = e^(-0.0079 * t)
0.8 = e^(-0.0079 * t)
Logarithm both sides (because ln(e) = 1:
ln(0.8) = ln(e^(-0.0079 * t))
ln(0.8) = (-0.0079 * t) * ln(e)
-0.223 = -0.0079 * t
t = -0.223 / -0.0079
t = 28.23
t ≈ 28 years
Answer:
3/2y -5
Step-by-step explanation:
-1/2 (-3y+10)
Distribute
-1/2* -3y + -1/2*10
3/2y -5
Answer:Median 6
Range 5
Interquartile range 3.5
Which is true the value are clustered around the median
Step-by-step explanation:
