Treat x^4 as the square of p: x^4 = p^2.
Then x^4 - 5x^2 - 36 = 0 becomes p^2 - 5p - 36 = 0.
This factors nicely, to (p-9)(p+4) = 0. Then p = 9 and p = -4.
Equating 9 and x^2, we find that x=3 or x=-3.
Equating -4 and x^2, we see that there's no real solution.
Show that both x=3 and x=-3 are real roots of x^4 - 5x^2 - 36 = 0.
Top box is 2x
bottom box is 3
Answer:
a=18-3 and b=32÷8
Step-by-step explanation:
the first one
Answer:
13 players
Step-by-step explanation:
Money Raised=RentedBus+Meals
1319.25=776.50+41.75p (p is for the number of players)(Now we solve for x)
Subtract 776.50 from both sides: 542.75=41.75x
Divide both sides by 41.75: 13=x
Remember that x is for the number of players so there'll be 13 players going to the tournament.
Could you take a little bit clear picture? :)
