Answer:
n=178/19
Step-by-step explanation:
Let me know if this helps
# Sin θ = 9/15.
# Cos θ = 12/15.
# Cosec θ = 15/9.
# Sec θ = 5/4
Step-by-step explanation:
![by \: using \: pythagorian \: triplets](https://tex.z-dn.net/?f=by%20%5C%3A%20using%20%5C%3A%20pythagorian%20%5C%3A%20triplets)
![{a}^{2} + {b}^{2} = {c}^{2}](https://tex.z-dn.net/?f=%20%7Ba%7D%5E%7B2%7D%20%20%2B%20%20%7Bb%7D%5E%7B2%7D%20%20%3D%20%20%7Bc%7D%5E%7B2%7D%20)
![{9}^{2} + {12}^{2} = {c}^{2}](https://tex.z-dn.net/?f=%20%7B9%7D%5E%7B2%7D%20%20%2B%20%20%7B12%7D%5E%7B2%7D%20%20%3D%20%20%7Bc%7D%5E%7B2%7D%20)
![81 + 144 = {c}^{2}](https://tex.z-dn.net/?f=81%20%2B%20144%20%3D%20%20%7Bc%7D%5E%7B2%7D%20)
![225 = {c}^{2}](https://tex.z-dn.net/?f=225%20%3D%20%20%7Bc%7D%5E%7B2%7D%20)
![c = 15.](https://tex.z-dn.net/?f=c%20%3D%2015.)
![\sin θ = \frac{9}{15}](https://tex.z-dn.net/?f=%20%5Csin%20%CE%B8%20%3D%20%20%5Cfrac%7B9%7D%7B15%7D%20)
![\cos θ = \frac{12}{15} = \frac{4}{5}](https://tex.z-dn.net/?f=%20%5Ccos%20%CE%B8%20%3D%20%20%5Cfrac%7B12%7D%7B15%7D%20%20%3D%20%20%5Cfrac%7B4%7D%7B5%7D%20)
![\csc θ = \frac{15}{9}](https://tex.z-dn.net/?f=%20%5Ccsc%20%CE%B8%20%3D%20%20%5Cfrac%7B15%7D%7B9%7D%20)
![\secθ = \frac{5}{4}](https://tex.z-dn.net/?f=%20%5Csec%CE%B8%20%3D%20%20%5Cfrac%7B5%7D%7B4%7D%20)
Answer:
![y+5 = \frac{1}{15}(x - 3)}](https://tex.z-dn.net/?f=y%2B5%20%3D%20%5Cfrac%7B1%7D%7B15%7D%28x%20-%203%29%7D)
Step-by-step explanation:
Given
-- Slope
--- Point
Required
Write an equation in point slope form
The point slope form of an equation is:
![y - y_1 = m(x - x_1)](https://tex.z-dn.net/?f=y%20-%20y_1%20%3D%20m%28x%20-%20x_1%29)
Substitute values for y1, x1 and m
![y-(-5) = \frac{1}{15}(x - 3)}](https://tex.z-dn.net/?f=y-%28-5%29%20%3D%20%5Cfrac%7B1%7D%7B15%7D%28x%20-%203%29%7D)
![y+5 = \frac{1}{15}(x - 3)}](https://tex.z-dn.net/?f=y%2B5%20%3D%20%5Cfrac%7B1%7D%7B15%7D%28x%20-%203%29%7D)
Hence, the equation in point slope form is:
![y+5 = \frac{1}{15}(x - 3)}](https://tex.z-dn.net/?f=y%2B5%20%3D%20%5Cfrac%7B1%7D%7B15%7D%28x%20-%203%29%7D)
I think the answer it would be D